django - files - dropzone js ejemplo

Intentando usar django y dropzone/

Question

Estoy tratando de usar dropzone.js con django.

Estoy siguiendo la guía un tanto anticuada aquí ( https://amatellanes.wordpress.com/2013/11/05/dropzonejs-django-how-to-build-a-file-upload-form/ )

Sospecho fuertemente que Mi punto de vista está en cuestión.

def test(request):
print "test view has been called"
if request.method == ''POST'':
print "test request method is POST"
form = UploadFileForm(request.POST, request.FILES)
print request
print request.FILES
if form.is_valid():
new_file = AttachedFiles(attachedfile=request.FILES[''file''])
new_file.save()
id = new_file.pk
print id
print "test form valid"
return HttpResponse(json.dumps({''id'': id}), content_type="application/json")
print "test form not valid"
else:
form = UploadFileForm()
data = {''form'': form}
return render_to_response(''mediamanager/test.html'', data, context_instance=RequestContext(request))

He probado enviarlo con el código dropzone

 <!-- IMPORTANT enctype attribute! -->
<form id="my_dropzone" class="dropzone" action="/mediamanager/test/" method="post" enctype="multipart/form-data">
{% csrf_token %}
<button id="submit-all">
Submit all files
</button>
</form>
<script src="{% static ''dropzone/js/dropzone.js'' %}"></script>
<script type="text/javascript">
Dropzone.options.myDropzone = {
// Prevents Dropzone from uploading dropped files immediately
autoProcessQueue : true,
init : function() {
var submitButton = document.querySelector("#submit-all")
myDropzone = this;
submitButton.addEventListener("click", function() {
myDropzone.processQueue();
// Tell Dropzone to process all queued files.
});
// You might want to show the submit button only when
// files are dropped here:
this.on("addedfile", function() {
// Show submit button here and/or inform user to click it.
console.log("blah")
});
}
};
</script>

y una forma básica

<form action="{% url "test" %}" method="post" enctype="multipart/form-data">
{% csrf_token %}
<input type="file" name="file" />
<input type="submit" value="Submit">
</form>

Y la forma nunca es válida. Estoy usando un modelo como se sugirió

class UploadFileForm(forms.ModelForm):
class Meta:
model = AttachedFiles

Answer 1

Tengo dropzone js trabajando modificando el ejemplo de arranque (estoy usando el programa de arranque) aquí: http://www.dropzonejs.com/bootstrap.html

No uso formularios. Obtuve una vista manejando los próximos mensajes ajax de dropzone. Aquí está la esencia de mi código de vista:

class AjaxUploadView(View):
"""
View for uploading via AJAX.
"""
def post_ajax(self, request, *args, **kwargs):
uploaded_file = request.FILES[''file'']
# Do stuff with file
# Return appropriate response

Espero eso ayude.

Answer 2

Puede gestionar las publicaciones de Dropzone como cualquier otra publicación de formulario de varias partes.

Así es como procedo:

@login_required
@usertype_required
def upload_picture(request, uid=None):
"""
Photo upload / dropzone handler
:param request:
:param uid: Optional picture UID when re-uploading a file.
:return:
"""
form = PhotoUploadForm(request.POST, request.FILES or None)
if form.is_valid():
pic = request.FILES[''file'']
# [...] Process whatever you do with that file there. I resize it, create thumbnails, etc.
# Get an instance of picture model (defined below)
picture = ...
picture.file = pic
picture.save()
return HttpResponse(''Image upload succeeded.'')
return HttpResponseBadRequest("Image upload form not valid.")

La forma es muy simple

class PhotoUploadForm(forms.Form):
#Keep name to ''file'' because that''s what Dropzone is using
file = forms.ImageField(required=True)

En tu modelo necesitas el upload_to set:

class Picture(models.Model):
[...]
# Original
file = models.ImageField(upload_to=get_upload_path)

Y aquí está mi creador de ruta de carga, pero puedes poner cualquier cosa

def get_upload_path(instance, filename):
""" creates unique-Path & filename for upload """
ext = filename.split(''.'')[-1]
filename = "%s.%s" % (instance.p_uid, ext)
d = datetime.date.today()
username = instance.author.username
#Create the directory structure
return os.path.join(
''userpics'', username, d.strftime(''%Y''), d.strftime(''%m''), filename
)

No olvides csrf_token en el formulario html mismo (estoy usando una directiva angularJS además de eso, será diferente para ti)

<form action="{% url ''upload_picture'' %}" class="dropzone" drop-zone>
{% csrf_token %}
<div class="fallback">
<h3>Your browser is not supported.</h3>
<strong>
<a href="https://browser-update.org/update.html" target="_blank">Click here for instructions on how to update it.</a>
</strong>
<p>You can still try to upload your pictures through this form: </p>
<p>
<input name="file" type="file" multiple />
<input type="submit" value="Upload" />
</p>
</div>
</form>