swift - constructors - no puede subindicar un valor de tipo NSDictionary con un índice de tipo cadena

swift super

Question

    var url: NSURL = NSURL(string: urlPath)!

    var request: NSMutableURLRequest = NSMutableURLRequest(URL: url)
    request.setValue("Basic /(base64EncodedCredential)", forHTTPHeaderField: "Authorization")
    request.HTTPMethod = "GET"

    var dataVal: NSData =  NSURLConnection.sendSynchronousRequest(request, returningResponse: nil, error:nil)!

    var err: NSError
    println(dataVal)


    //var jsonResult : NSDictionary?
    var jsonResult  = NSJSONSerialization.JSONObjectWithData(dataVal, options: NSJSONReadingOptions.MutableContainers, error: nil) as? NSDictionary

    println("Synchronous  /(jsonResult)")
    jsonResult["records"] 

Aquí es donde ocurre el error, solo quiero tomar un valor de mi jsonResult , que se imprime correctamente en la consola.

Answer 1

Está encasillando el jsonResult como NSDictionary , en su lugar use [String:AnyObject]

Si está utilizando NSDictionary , debe usar los valueForKey(key) u objectForKey(key) de NSDictionary para obtener el valor de la clave.

    var url: NSURL = NSURL(string: urlPath)!
    var err: NSError?

        var request: NSMutableURLRequest = NSMutableURLRequest(URL: url)
        request.setValue("Basic /(base64EncodedCredential)", forHTTPHeaderField: "Authorization")
        request.HTTPMethod = "GET"

        var dataVal: NSData =  NSURLConnection.sendSynchronousRequest(request, returningResponse: nil, error:nil)!

        var err: NSError
        println(dataVal)


        //var jsonResult : NSDictionary?
        var jsonResult:AnyObject?  = NSJSONSerialization.JSONObjectWithData(dataVal, options: NSJSONReadingOptions.MutableLeaves, error: &err)  

        println("Synchronous  /(jsonResult)")
        if let result = jsonResult as? [String: AnyObject] {
           if let oneValue = result["records"] as? String { //Here i am considering value for jsonResult["records"] as String, if it other than String, please change it.
             println(oneValue)
           }
       }