ios - saber - lector de coordenadas

Obtener latitud/longitud de la dirección

Question

¿Cómo puedo obtener la latitud y longitud de una dirección completa (calle, ciudad, etc.) ingresada por el usuario, utilizando el iPhone SDK 3.x?

Answer 1

Aquí hay una solución similar para obtener la latitud y longitud de Google. Nota: este ejemplo utiliza la biblioteca SBJson, que puede encontrar en github:

+ (CLLocationCoordinate2D) geoCodeUsingAddress: (NSString *) address
{
CLLocationCoordinate2D myLocation;
// -- modified from the page - we use the SBJson parser instead of the string scanner --
NSString *esc_addr = [address stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding];
NSString *req = [NSString stringWithFormat: @"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];
NSDictionary *googleResponse = [[NSString stringWithContentsOfURL: [NSURL URLWithString: req] encoding: NSUTF8StringEncoding error: NULL] JSONValue];
NSDictionary *resultsDict = [googleResponse valueForKey: @"results"]; // get the results dictionary
NSDictionary *geometryDict = [ resultsDict valueForKey: @"geometry"]; // geometry dictionary within the results dictionary
NSDictionary *locationDict = [ geometryDict valueForKey: @"location"]; // location dictionary within the geometry dictionary
// -- you should be able to strip the latitude & longitude from google''s location information (while understanding what the json parser returns) --
DLog (@"-- returning latitude & longitude from google --");
NSArray *latArray = [locationDict valueForKey: @"lat"]; NSString *latString = [latArray lastObject]; // (one element) array entries provided by the json parser
NSArray *lngArray = [locationDict valueForKey: @"lng"]; NSString *lngString = [lngArray lastObject]; // (one element) array entries provided by the json parser
myLocation.latitude = [latString doubleValue]; // the json parser uses NSArrays which don''t support "doubleValue"
myLocation.longitude = [lngString doubleValue];
return myLocation;
}

Answer 2

Aquí hay una versión actualizada, más compacta, del código de Nevergiven, que utiliza la última API v3:

- (CLLocationCoordinate2D) geoCodeUsingAddress:(NSString *)address
{
double latitude = 0, longitude = 0;
NSString *esc_addr = [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *req = [NSString stringWithFormat:@"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];
NSString *result = [NSString stringWithContentsOfURL:[NSURL URLWithString:req] encoding:NSUTF8StringEncoding error:NULL];
if (result) {
NSScanner *scanner = [NSScanner scannerWithString:result];
if ([scanner scanUpToString:@"/"lat/" :" intoString:nil] && [scanner scanString:@"/"lat/" :" intoString:nil]) {
[scanner scanDouble:&latitude];
if ([scanner scanUpToString:@"/"lng/" :" intoString:nil] && [scanner scanString:@"/"lng/" :" intoString:nil]) {
[scanner scanDouble:&longitude];
}
}
}
CLLocationCoordinate2D center;
center.latitude = latitude;
center.longitude = longitude;
return center;
}

Supone que las coordenadas de "ubicación" son lo primero, por ejemplo, antes que las de "ventana gráfica", porque solo toma las primeras coordenadas que encuentra debajo de las teclas "lng" y "lat". Siéntase libre de usar un escáner JSON adecuado (por ejemplo, SBJSON) si está preocupado por esta sencilla técnica de escaneo que se usa aquí.

Answer 3

El siguiente método hace lo que pediste. Debe insertar la clave de Google Maps para que esto funcione correctamente.

- (CLLocationCoordinate2D) geoCodeUsingAddress:(NSString *)address{
int code = -1;
int accuracy = -1;
float latitude = 0.0f;
float longitude = 0.0f;
CLLocationCoordinate2D center;
// setup maps api key
NSString * MAPS_API_KEY = @"YOUR GOOGLE MAPS KEY HERE";
NSString *escaped_address = [address stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding];
// Contact Google and make a geocoding request
NSString *requestString = [NSString stringWithFormat:@"http://maps.google.com/maps/geo?q=%@&output=csv&oe=utf8&key=%@&sensor=false&gl=it", escaped_address, MAPS_API_KEY];
NSURL *url = [NSURL URLWithString:requestString];
NSString *result = [NSString stringWithContentsOfURL: url encoding: NSUTF8StringEncoding error:NULL];
if(result){
// we got a result from the server, now parse it
NSScanner *scanner = [NSScanner scannerWithString:result];
[scanner scanInt:&code];
if(code == 200){
// everything went off smoothly
[scanner scanString:@"," intoString:nil];
[scanner scanInt:&accuracy];
//NSLog(@"Accuracy: %d", accuracy);
[scanner scanString:@"," intoString:nil];
[scanner scanFloat:&latitude];
[scanner scanString:@"," intoString:nil];
[scanner scanFloat:&longitude];
center.latitude = latitude;
center.longitude = longitude;
return center;
}
else{
// the server answer was not the one we expected
UIAlertView *alert = [[[UIAlertView alloc]
initWithTitle: @"Warning"
message:@"Connection to Google Maps failed"
delegate:nil
cancelButtonTitle:nil
otherButtonTitles:@"OK", nil] autorelease];
[alert show];
center.latitude = 0.0f;
center.longitude = 0.0f;
return center;
}
}
else{
// no result back from the server
UIAlertView *alert = [[[UIAlertView alloc]
initWithTitle: @"Warning"
message:@"Connection to Google Maps failed"
delegate:nil
cancelButtonTitle:nil
otherButtonTitles:@"OK", nil] autorelease];
[alert show];
center.latitude = 0.0f;
center.longitude = 0.0f;
return center;
}
}
center.latitude = 0.0f;
center.longitude = 0.0f;
return center;
}

Answer 4

Para la solución clave de Google Map, tal como se describe en el artículo no perdonado, ¿no es necesario que la aplicación sea gratuita? Según los términos y condiciones de Google: 9.1. Accesibilidad pública y gratuita a la implementación de la API de Google Maps. La implementación de la API de Google Maps debe ser generalmente accesible para los usuarios sin cargo.

Con el kit de mapas en SDK 3.0, esto se hace fácilmente usando el SDK. Consulte los manuales de Apple o siga: http://www.devworld.apple.com/iphone/program/sdk/maps.html

Answer 5

Puedes usar Google Geocoding para esto . Es tan simple como obtener datos a través de HTTP y analizarlos (puede devolver JSON KML, XML, CSV).

Answer 6

También está CoreGeoLocation, que envuelve la funcionalidad en un marco (Mac) o biblioteca estática (iPhone). Admite búsquedas a través de Google o Yahoo, si tiene una preferencia por una sobre la otra.

http://github.com/thekarladam/CoreGeoLocation

Answer 7

Versión de actualización, usando iOS JSON:

- (CLLocationCoordinate2D)getLocation:(NSString *)address {
CLLocationCoordinate2D center;
NSString *esc_addr = [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *req = [NSString stringWithFormat:@"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];
NSData *responseData = [[NSData alloc] initWithContentsOfURL:
[NSURL URLWithString:req]]; NSError *error;
NSMutableDictionary *responseDictionary = [NSJSONSerialization
JSONObjectWithData:responseData
options:nil
error:&error];
if( error )
{
NSLog(@"%@", [error localizedDescription]);
center.latitude = 0;
center.longitude = 0;
return center;
}
else {
NSArray *results = (NSArray *) responseDictionary[@"results"];
NSDictionary *firstItem = (NSDictionary *) [results objectAtIndex:0];
NSDictionary *geometry = (NSDictionary *) [firstItem objectForKey:@"geometry"];
NSDictionary *location = (NSDictionary *) [geometry objectForKey:@"location"];
NSNumber *lat = (NSNumber *) [location objectForKey:@"lat"];
NSNumber *lng = (NSNumber *) [location objectForKey:@"lng"];
center.latitude = [lat doubleValue];
center.longitude = [lng doubleValue];
return center;
}
}

Answer 8

func geoCodeUsingAddress(address: NSString) -> CLLocationCoordinate2D {
var latitude: Double = 0
var longitude: Double = 0
let addressstr : NSString = "http://maps.google.com/maps/api/geocode/json?sensor=false&address=/(address)" as NSString
let urlStr = addressstr.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed)
let searchURL: NSURL = NSURL(string: urlStr! as String)!
do {
let newdata = try Data(contentsOf: searchURL as URL)
if let responseDictionary = try JSONSerialization.jsonObject(with: newdata, options: []) as? NSDictionary {
print(responseDictionary)
let array = responseDictionary.object(forKey: "results") as! NSArray
let dic = array[0] as! NSDictionary
let locationDic = (dic.object(forKey: "geometry") as! NSDictionary).object(forKey: "location") as! NSDictionary
latitude = locationDic.object(forKey: "lat") as! Double
longitude = locationDic.object(forKey: "lng") as! Double
}} catch {
}
var center = CLLocationCoordinate2D()
center.latitude = latitude
center.longitude = longitude
return center
}

Answer 9

- (void)viewDidLoad
{
app=(AppDelegate *)[[UIApplication sharedApplication] delegate];
NSLog(@"%@", app.str_address);
NSLog(@"internet connect");
NSString *Str_address=_txt_zipcode.text;
double latitude1 = 0, longitude1 = 0;
NSString *esc_addr = [ Str_address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *req = [NSString stringWithFormat:@"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];
NSString *result = [NSString stringWithContentsOfURL:[NSURL URLWithString:req] encoding:NSUTF8StringEncoding error:NULL];
if (result)
{
NSScanner *scanner = [NSScanner scannerWithString:result];
if ([scanner scanUpToString:@"/"lat/" :" intoString:nil] && [scanner scanString:@"/"lat/" :" intoString:nil])
{
[scanner scanDouble:&latitude1];
if ([scanner scanUpToString:@"/"lng/" :" intoString:nil] && [scanner scanString:@"/"lng/" :" intoString:nil])
{
[scanner scanDouble:&longitude1];
}
}
}
//in #.hfile
// CLLocationCoordinate2D lat;
// CLLocationCoordinate2D lon;
// float address_latitude;
// float address_longitude;
lat.latitude=latitude1;
lon.longitude=longitude1;
address_latitude=lat.latitude;
address_longitude=lon.longitude;
}