query - sql server delete duplicate rows but keep one

Ayuda de eliminación de SQL Query Duplicate

Question

Necesito eliminar registros semi duplicados de la siguiente tabla

ID      PID      SCORE
1       1        50
2       33       20
3       1        90
4       5        55
5       7        11
6       22       34

Para cualquier PID duplicado que exista, quiero eliminar el registro de menor puntaje. En el ejemplo anterior, ID 1 sería eliminado. Intento encontrar una forma de hacerlo sin usar bucles pero realmente estoy luchando.

Cualquier ayuda sería apreciada.

Gracias

Answer 1

No puedo ver tu consulta, así que hice este ejemplo ...

SELECT
    PID,
    MAX(Score)
FROM
    tblTable
GROUP BY
    PID

Answer 2

prueba esto..

    declare @tt table(id int, pid int,score int)
    insert into @tt
    select 1,1,50 union all
    select 2,33,50 union all
    select 8,33,80 union all
    select 3,1,90 union all
    select 4,5,50 union all
    select 5,5,10 union all
    select 6,6,10 union all
    select 7,6,50  
    ---------   
    delete from @tt where id in (
    select t1.id from @tt t1 inner join
    (
        select  MIN(score) tScore,pid tPid from @tt where pid in 
        (select  pid from @tt group by pid having count (pid) > 1) group by pid 
    ) t2 on t1.pid=t2.tPid and t1.score=t2.tScore)

    select * from @tt

Answer 3

WITH    q AS
        (
        SELECT  *, ROW_NUMBER() OVER (PARTITION BY pid ORDER BY score) AS rn
        FROM    mytable
        )
DELETE
FROM    q
WHERE   rn = 1

Para dejar los resultados que no tienen duplicados:

WITH    q AS
        (
        SELECT  *,
                ROW_NUMBER() OVER (PARTITION BY pid ORDER BY score) AS rn,
                COUNT(*) OVER (PARTITION BY pid) AS cnt
        FROM    mytable
        )
DELETE
FROM    q
WHERE   rn = 1
        AND cnt > 1

Answer 4

    DELETE t.* 
    FROM Table1 t 
    JOIN (SELECT pid, MIN(score) minScore, MAX(id) maxId
            FROM Table1
        GROUP BY pid) t1 
    ON t.pid = t1.pid 
   AND t.score = t1.minScore 
   AND t.id < t1.maxId