java - tables - join hibernate criteria

HQL Hibernate INNER JOIN

Question

¿Cómo puedo escribir esta consulta SQL en Hibernate? Me gustaría usar Hibernate para crear consultas, no crear la base de datos.

SELECT * FROM Employee e INNER JOIN Team t ON e.Id_team=t.Id_team

Creé clases de entidad en SQLServer2008,

@Entity
@Table(name="EMPLOYEE")
public class Employee
{
    @Id @GeneratedValue
    @Column(name="ID_EMPLOYEE")
    private int id_employee;
    @Column(name="SURNAME")
    private String surname;
    @Column(name="FIRSTNAME")
    private String firstname;
    @Column(name="ID_PROFESSION")
    private int id_profession;
    @Column(name="ID_BOSS")
    private int id_boss;
    @Column(name="HIRED_DATE")
    private Date hired;
    @Column(name="SALARY")
    private double salary;
    @Column(name="SALARY_ADD")
    private double salary_add;
    @Column(name="ID_TEAM")
    private int id_team;
    //setters and getters
}

@Entity
@Table(name="TEAM")
public class Team
{
    @Id @GeneratedValue
    @Column(name="ID_TEAM")
    private int id_team;
    @Column(name="TEAMNAME")
    private String teamname;
    @Column(name="ADDRESS")
    private String address;
    //setters and getters
}

Intenté crear una consulta de selección de trabajo de muchas maneras, pero todavía no funciona.

SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory();
Session session = sessionFactory.openSession();                 
session.beginTransaction();
String select = "FROM Employee e INNER JOIN Team t ON e.Id_team=t.Id_team";
Query query = session.createQuery(select);
List elist = query.list();
session.getTransaction().commit();
session.close();    

¿Tal vez algo está mal con las entidades?

Answer 1

Las combinaciones solo se pueden utilizar cuando existe una asociación entre entidades. Su entidad de empleado no debe tener un campo llamado id_team , de tipo int , asignado a una columna. Debe tener una asociación ManyToOne con la entidad del Equipo, asignada como JoinColumn:

@ManyToOne
@JoinColumn(name="ID_TEAM")
private Team team;

Entonces, la siguiente consulta funcionará perfectamente:

select e from Employee e inner join e.team

Que cargará a todos los empleados, excepto aquellos que no estén asociados a ningún equipo.

Lo mismo ocurre con todos los otros campos que son una clave externa a alguna otra tabla asignada como una entidad, por supuesto ( id_boss , id_profession ).

Es hora de que lea la documentación de Hibernate, porque se perdió una parte extremadamente importante de lo que es y cómo funciona.

Answer 2

Puede hacerlo sin tener que crear un mapeo real de Hibernate. Prueba esto:

SELECT * FROM Employee e, Team t WHERE e.Id_team=t.Id_team

Answer 3

import java.io.Serializable;
import java.util.ArrayList;
import java.util.List;
import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.OneToMany;
import javax.persistence.Table;

@Entity
@Table(name="empTable")
public class Employee implements Serializable{
private static final long serialVersionUID = 1L;
private int id;
private String empName;

List<Address> addList=new ArrayList<Address>();


@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
@Column(name="emp_id")
public int getId() {
    return id;
}
public void setId(int id) {
    this.id = id;
}
public String getEmpName() {
    return empName;
}
public void setEmpName(String empName) {
    this.empName = empName;
}

@OneToMany(mappedBy="employee",cascade=CascadeType.ALL)
public List<Address> getAddList() {
    return addList;
}

public void setAddList(List<Address> addList) {
    this.addList = addList;
}
}

Tenemos dos entidades Empleado y Dirección con relación One to Many.

import java.io.Serializable;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;
import javax.persistence.Table;

@Entity
@Table(name="address")
public class Address implements Serializable{

private static final long serialVersionUID = 1L;

private int address_id;
private String address;
Employee employee;

@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
public int getAddress_id() {
    return address_id;
}
public void setAddress_id(int address_id) {
    this.address_id = address_id;
}
public String getAddress() {
    return address;
}
public void setAddress(String address) {
    this.address = address;
}

@ManyToOne
@JoinColumn(name="emp_id")
public Employee getEmployee() {
    return employee;
}
public void setEmployee(Employee employee) {
    this.employee = employee;
}
}

De esta manera podemos implementar la unión interna entre dos tablas.

import java.util.List;
import org.hibernate.Query;
import org.hibernate.Session;

public class Main {

public static void main(String[] args) {
    saveEmployee();

    retrieveEmployee();

}

private static void saveEmployee() {
    Employee employee=new Employee();
    Employee employee1=new Employee();
    Employee employee2=new Employee();
    Employee employee3=new Employee();

    Address address=new Address();
    Address address1=new Address();
    Address address2=new Address();
    Address address3=new Address();

    address.setAddress("1485,Sector 42 b");
    address1.setAddress("1485,Sector 42 c");
    address2.setAddress("1485,Sector 42 d");
    address3.setAddress("1485,Sector 42 a");

    employee.setEmpName("Varun");
    employee1.setEmpName("Krishan");
    employee2.setEmpName("Aasif");
    employee3.setEmpName("Dut");

    address.setEmployee(employee);
    address1.setEmployee(employee1);
    address2.setEmployee(employee2);
    address3.setEmployee(employee3);

    employee.getAddList().add(address);
    employee1.getAddList().add(address1);
    employee2.getAddList().add(address2);
    employee3.getAddList().add(address3);

    Session session=HibernateUtil.getSessionFactory().openSession();

    session.beginTransaction();

    session.save(employee);
    session.save(employee1);
    session.save(employee2);
    session.save(employee3);
    session.getTransaction().commit();
    session.close();
}

private static void retrieveEmployee() {
    try{

    String sqlQuery="select e from Employee e inner join e.addList";

    Session session=HibernateUtil.getSessionFactory().openSession();

    Query query=session.createQuery(sqlQuery);

    List<Employee> list=query.list();

     list.stream().forEach((p)->{System.out.println(p.getEmpName());});     
    session.close();
    }catch(Exception e){
        e.printStackTrace();
    }
}
}

He usado Java 8 para bucle para editar los nombres. Asegúrese de tener jdk 1.8 con tomcat 8. También agregue algunos registros más para una mejor comprensión.

 public class HibernateUtil {
 private static SessionFactory sessionFactory ;
 static {
    Configuration configuration = new Configuration();

    configuration.addAnnotatedClass(Employee.class);
    configuration.addAnnotatedClass(Address.class);
                  configuration.setProperty("connection.driver_class","com.mysql.jdbc.Driver");
    configuration.setProperty("hibernate.connection.url", "jdbc:mysql://localhost:3306/hibernate");                                
    configuration.setProperty("hibernate.connection.username", "root");     
    configuration.setProperty("hibernate.connection.password", "root");
    configuration.setProperty("dialect", "org.hibernate.dialect.MySQLDialect");
    configuration.setProperty("hibernate.hbm2ddl.auto", "update");
    configuration.setProperty("hibernate.show_sql", "true");
    configuration.setProperty(" hibernate.connection.pool_size", "10");


   // configuration
    StandardServiceRegistryBuilder builder = new StandardServiceRegistryBuilder().applySettings(configuration.getProperties());
    sessionFactory = configuration.buildSessionFactory(builder.build());
 }
public static SessionFactory getSessionFactory() {
    return sessionFactory;
}
}