python - jupiter - jupyter notebook install conda
pyzmq falta al ejecutar el cuaderno ipython (3)
Puedo ejecutar iPython, pero cuando intento iniciar una notebook, aparece el siguiente error:
~ ipython notebook
Traceback (most recent call last):
File "/usr/local/bin/ipython", line 8, in <module>
load_entry_point(''ipython==2.1.0'', ''console_scripts'', ''ipython'')()
File "/Library/Python/2.7/site-packages/ipython-2.1.0-py2.7.egg/IPython/__init__.py", line 120, in start_ipython
return launch_new_instance(argv=argv, **kwargs)
File "/Library/Python/2.7/site-packages/ipython-2.1.0-py2.7.egg/IPython/config/application.py", line 563, in launch_instance
app.initialize(argv)
File "<string>", line 2, in initialize
File "/Library/Python/2.7/site-packages/ipython-2.1.0-py2.7.egg/IPython/config/application.py", line 92, in catch_config_error
return method(app, *args, **kwargs)
File "/Library/Python/2.7/site-packages/ipython-2.1.0-py2.7.egg/IPython/terminal/ipapp.py", line 321, in initialize
super(TerminalIPythonApp, self).initialize(argv)
File "<string>", line 2, in initialize
File "/Library/Python/2.7/site-packages/ipython-2.1.0-py2.7.egg/IPython/config/application.py", line 92, in catch_config_error
return method(app, *args, **kwargs)
File "/Library/Python/2.7/site-packages/ipython-2.1.0-py2.7.egg/IPython/core/application.py", line 381, in initialize
self.parse_command_line(argv)
File "/Library/Python/2.7/site-packages/ipython-2.1.0-py2.7.egg/IPython/terminal/ipapp.py", line 316, in parse_command_line
return super(TerminalIPythonApp, self).parse_command_line(argv)
File "<string>", line 2, in parse_command_line
File "/Library/Python/2.7/site-packages/ipython-2.1.0-py2.7.egg/IPython/config/application.py", line 92, in catch_config_error
return method(app, *args, **kwargs)
File "/Library/Python/2.7/site-packages/ipython-2.1.0-py2.7.egg/IPython/config/application.py", line 475, in parse_command_line
return self.initialize_subcommand(subc, subargv)
File "<string>", line 2, in initialize_subcommand
File "/Library/Python/2.7/site-packages/ipython-2.1.0-py2.7.egg/IPython/config/application.py", line 92, in catch_config_error
return method(app, *args, **kwargs)
File "/Library/Python/2.7/site-packages/ipython-2.1.0-py2.7.egg/IPython/config/application.py", line 406, in initialize_subcommand
subapp = import_item(subapp)
File "/Library/Python/2.7/site-packages/ipython-2.1.0-py2.7.egg/IPython/utils/importstring.py", line 42, in import_item
module = __import__(package, fromlist=[obj])
File "/Library/Python/2.7/site-packages/ipython-2.1.0-py2.7.egg/IPython/html/notebookapp.py", line 39, in <module>
check_for_zmq(''2.1.11'', ''IPython.html'')
File "/Library/Python/2.7/site-packages/ipython-2.1.0-py2.7.egg/IPython/utils/zmqrelated.py", line 37, in check_for_zmq
raise ImportError("%s requires pyzmq >= %s"%(required_by, minimum_version))
ImportError: IPython.html requires pyzmq >= 2.1.11
Pero, por lo que puedo ver, ya tengo el paquete pyzmq instalado.
~ pip install pyzmq
Requirement already satisfied (use --upgrade to upgrade): pyzmq in /Library/Python/2.7/site-packages/pyzmq-14.3.1-py2.7-macosx-10.6-intel.egg
Cleaning up...
Arg. La instalación de ipython es un poco idiosincrásica. Esto es lo que tuve que hacer para resolver esto:
$ pip uninstall ipython
$ pip install "ipython[all]"
El problema es que los portátiles tienen su propio conjunto de dependencias, que no están instaladas con pip install ipython
. Sin embargo, al haber instalado ipython , pip no ve la necesidad de agregar nada si luego prueba el formulario [all]
.
Como se menciona en los comentarios para algunos shells (por ejemplo, zsh), es necesario escapar o citar los corchetes (la pip install ipython/[all/]
también funcionaría).
Para mí (Ubuntu 14.04.2) funcionó la instalación de synaptic package manager: el paquete se llama python3-zmq, con este paquete se instalará libzmq3.
Después de eso, compruebe si pyzmq está instalado correctamente:
pip list
Luego instalé ipython:
pip install "ipython[all]"
Utilizando
ipython2.7 notebook
En lugar de
ipython notebook
¿El truco para mí?