example - webrequest post c# json

Cómo hacer una solicitud web HTTP POST

Question

¿Cómo puedo realizar una solicitud HTTP y enviar algunos datos utilizando el método POST ? Puedo hacer una solicitud GET pero no tengo idea de cómo hacer un POST .

Answer 1

Cuando se usa el espacio de nombres Windows.Web.Http , para POST en lugar de FormUrlEncodedContent escribimos HttpFormUrlEncodedContent. También la respuesta es tipo de HttpResponseMessage. El resto es como escribió Evan Mulawski.

Answer 2

Este es un ejemplo completo de trabajo de envío / recepción de datos en formato JSON. Usé VS2013 Express Edition.

using System;
using System.Collections.Generic;
using System.Data;
using System.Data.OleDb;
using System.IO;
using System.Linq;
using System.Net.Http;
using System.Text;
using System.Threading.Tasks;
using System.Web.Script.Serialization;

namespace ConsoleApplication1
{
    class Customer
    {
        public string Name { get; set; }
        public string Address { get; set; }
        public string Phone { get; set; }
    }

    public class Program
    {
        private static readonly HttpClient _Client = new HttpClient();
        private static JavaScriptSerializer _Serializer = new JavaScriptSerializer();

        static void Main(string[] args)
        {
            Run().Wait();
        }

        static async Task Run()
        {
            string url = "http://www.example.com/api/Customer";
            Customer cust = new Customer() { Name = "Example Customer", Address = "Some example address", Phone = "Some phone number" };
            var json = _Serializer.Serialize(cust);
            var response = await Request(HttpMethod.Post, url, json, new Dictionary<string, string>());
            string responseText = await response.Content.ReadAsStringAsync();

            List<YourCustomClassModel> serializedResult = _Serializer.Deserialize<List<YourCustomClassModel>>(responseText);

            Console.WriteLine(responseText);
            Console.ReadLine();
        }

        /// <summary>
        /// Makes an async HTTP Request
        /// </summary>
        /// <param name="pMethod">Those methods you know: GET, POST, HEAD, etc...</param>
        /// <param name="pUrl">Very predictable...</param>
        /// <param name="pJsonContent">String data to POST on the server</param>
        /// <param name="pHeaders">If you use some kind of Authorization you should use this</param>
        /// <returns></returns>
        static async Task<HttpResponseMessage> Request(HttpMethod pMethod, string pUrl, string pJsonContent, Dictionary<string, string> pHeaders)
        {
            var httpRequestMessage = new HttpRequestMessage();
            httpRequestMessage.Method = pMethod;
            httpRequestMessage.RequestUri = new Uri(pUrl);
            foreach (var head in pHeaders)
            {
                httpRequestMessage.Headers.Add(head.Key, head.Value);
            }
            switch (pMethod.Method)
            {
                case "POST":
                    HttpContent httpContent = new StringContent(pJsonContent, Encoding.UTF8, "application/json");
                    httpRequestMessage.Content = httpContent;
                    break;

            }

            return await _Client.SendAsync(httpRequestMessage);
        }
    }
}

Answer 3

Hay algunas respuestas muy buenas aquí. Permítame publicar una manera diferente de configurar sus encabezados con el WebClient (). También te mostraré cómo configurar una clave API.

        var client = new WebClient();
        string credentials = Convert.ToBase64String(Encoding.ASCII.GetBytes(userName + ":" + passWord));
        client.Headers[HttpRequestHeader.Authorization] = $"Basic {credentials}";
        //If you have your data stored in an object serialize it into json to pass to the webclient with Newtonsoft''s JsonConvert
        var encodedJson = JsonConvert.SerializeObject(newAccount);

        client.Headers.Add($"x-api-key:{ApiKey}");
        client.Headers.Add("Content-Type:application/json");
        try
        {
            var response = client.UploadString($"{apiurl}", encodedJson);
            //if you have a model to deserialize the json into Newtonsoft will help bind the data to the model, this is an extremely useful trick for GET calls when you have a lot of data, you can strongly type a model and dump it into an instance of that class.
            Response response1 = JsonConvert.DeserializeObject<Response>(response);

Answer 4

Hay varias formas de realizar solicitudes HTTP GET y POST :

Método A: HttpClient

Disponible en: .NET Framework 4.5+, .NET Standard 1.1+, .NET Core 1.0+

Actualmente el enfoque preferido. Asincrónico. Versión portátil para otras plataformas disponibles a través de NuGet .

using System.Net.Http;

Preparar

Se recommended crear un HttpClient para la vida útil de su aplicación y compartirlo.

private static readonly HttpClient client = new HttpClient();

ENVIAR

var values = new Dictionary<string, string>
{
   { "thing1", "hello" },
   { "thing2", "world" }
};

var content = new FormUrlEncodedContent(values);

var response = await client.PostAsync("http://www.example.com/recepticle.aspx", content);

var responseString = await response.Content.ReadAsStringAsync();

OBTENER

var responseString = await client.GetStringAsync("http://www.example.com/recepticle.aspx");

Método B: Bibliotecas de terceros

RestSharp

Biblioteca probada y probada para interactuar con las API REST. Portátil. Disponible a través de NuGet .

Flurl.Http

Nueva biblioteca con una API fluida y ayudantes de pruebas. HttpClient bajo el capó. Portátil. Disponible a través de NuGet .

using Flurl.Http;

ENVIAR

var responseString = await "http://www.example.com/recepticle.aspx"
    .PostUrlEncodedAsync(new { thing1 = "hello", thing2 = "world" })
    .ReceiveString();

OBTENER

var responseString = await "http://www.example.com/recepticle.aspx"
    .GetStringAsync();

Método C: Legado

Disponible en: .NET Framework 1.1+, .NET Standard 2.0+, .NET Core 1.0+

using System.Net;
using System.Text;  // for class Encoding
using System.IO;    // for StreamReader

ENVIAR

var request = (HttpWebRequest)WebRequest.Create("http://www.example.com/recepticle.aspx");

var postData = "thing1=hello";
    postData += "&thing2=world";
var data = Encoding.ASCII.GetBytes(postData);

request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";
request.ContentLength = data.Length;

using (var stream = request.GetRequestStream())
{
    stream.Write(data, 0, data.Length);
}

var response = (HttpWebResponse)request.GetResponse();

var responseString = new StreamReader(response.GetResponseStream()).ReadToEnd();

OBTENER

var request = (HttpWebRequest)WebRequest.Create("http://www.example.com/recepticle.aspx");

var response = (HttpWebResponse)request.GetResponse();

var responseString = new StreamReader(response.GetResponseStream()).ReadToEnd();

Método D: WebClient (también ahora legado)

Disponible en: .NET Framework 1.1+, .NET Standard 2.0+, .NET Core 2.0+

using System.Net;
using System.Collections.Specialized;

ENVIAR

using (var client = new WebClient())
{
    var values = new NameValueCollection();
    values["thing1"] = "hello";
    values["thing2"] = "world";

    var response = client.UploadValues("http://www.example.com/recepticle.aspx", values);

    var responseString = Encoding.Default.GetString(response);
}

OBTENER

using (var client = new WebClient())
{
    var responseString = client.DownloadString("http://www.example.com/recepticle.aspx");
}

Answer 5

Puede usar IEnterprise.Easy-HTTP ya que tiene incorporado análisis de clase y creación de consultas:

await new RequestBuilder<ExampleObject>()
.SetHost("https://httpbin.org")
.SetContentType(ContentType.Application_Json)
.SetType(RequestType.Post)
.SetModelToSerialize(dto)
.Build()
.Execute();

Soy el autor de la biblioteca, así que no dude en hacer preguntas o consultar el código en github

Answer 6

Si te gusta la API fluida, puedes usar Tiny.RestClient que está disponible en Nuget

var client = new TinyRestClient(new HttpClient(), "http://MyAPI.com/api");
// POST
 var city = new City() { Name = "Paris" , Country = "France"};
// With content
var response = await client.PostRequest("City", city).
                ExecuteAsync<bool>();

¡Espero que ayude!

Answer 7

Solicitud GET simple

using System.Net;

...

using (var wb = new WebClient())
{
    var response = wb.DownloadString(url);
}

Solicitud POST simple

using System.Net;
using System.Collections.Specialized;

...

using (var wb = new WebClient())
{
    var data = new NameValueCollection();
    data["username"] = "myUser";
    data["password"] = "myPassword";

    var response = wb.UploadValues(url, "POST", data);
    string responseInString = Encoding.UTF8.GetString(response);
}

Answer 8

Solución simple (de una sola línea, sin comprobación de errores, sin espera de respuesta) que he encontrado hasta ahora

(new WebClient()).UploadStringAsync(new Uri(Address), dataString);‏

utilizar con precaución!

Answer 9

MSDN tiene una muestra.

using System;
using System.IO;
using System.Net;
using System.Text;

namespace Examples.System.Net
{
    public class WebRequestPostExample
    {
        public static void Main()
        {
            // Create a request using a URL that can receive a post. 
            WebRequest request = WebRequest.Create("http://www.contoso.com/PostAccepter.aspx");
            // Set the Method property of the request to POST.
            request.Method = "POST";
            // Create POST data and convert it to a byte array.
            string postData = "This is a test that posts this string to a Web server.";
            byte[] byteArray = Encoding.UTF8.GetBytes(postData);
            // Set the ContentType property of the WebRequest.
            request.ContentType = "application/x-www-form-urlencoded";
            // Set the ContentLength property of the WebRequest.
            request.ContentLength = byteArray.Length;
            // Get the request stream.
            Stream dataStream = request.GetRequestStream();
            // Write the data to the request stream.
            dataStream.Write(byteArray, 0, byteArray.Length);
            // Close the Stream object.
            dataStream.Close();
            // Get the response.
            WebResponse response = request.GetResponse();
            // Display the status.
            Console.WriteLine(((HttpWebResponse)response).StatusDescription);
            // Get the stream containing content returned by the server.
            dataStream = response.GetResponseStream();
            // Open the stream using a StreamReader for easy access.
            StreamReader reader = new StreamReader(dataStream);
            // Read the content.
            string responseFromServer = reader.ReadToEnd();
            // Display the content.
            Console.WriteLine(responseFromServer);
            // Clean up the streams.
            reader.Close();
            dataStream.Close();
            response.Close();
        }
    }
}

Answer 10

WebRequest usar la clase WebRequest y el método GetRequestStream .

Here hay un ejemplo.