iphone - segundos - Cómo calcular el tiempo en horas entre dos fechas en iOS

como calcular la edad de una persona en años meses y dias

Question

¿Cómo puedo calcular el tiempo transcurrido en horas entre dos veces (posiblemente en días diferentes) en iOS?

Answer 1

La función NSDate timeIntervalSinceDate: le dará la diferencia de dos fechas en segundos.

 NSDate* date1 = someDate;
 NSDate* date2 = someOtherDate;
 NSTimeInterval distanceBetweenDates = [date1 timeIntervalSinceDate:date2];
 double secondsInAnHour = 3600;
 NSInteger hoursBetweenDates = distanceBetweenDates / secondsInAnHour;

Vea, la biblioteca de referencia de apple http://developer.apple.com/library/mac/navigation/ o si está usando Xcode simplemente seleccione help / documentation del menú.

Ver: how-to-convert-an-nstimeinterval-seconds-into-minutes

--edit: consulta la respuesta de ÐąrέÐέvil a continuación para un manejo correcto del horario de verano / segundos de salto

Answer 2

Pago: se ocupa del horario de verano, año bisiesto, ya que usó el calendario de iOS para calcular. Puede cambiar la cadena y las condiciones para incluir minutos con horas y días.

+(NSString*)remaningTime:(NSDate*)startDate endDate:(NSDate*)endDate {

    NSDateComponents *components;
    NSInteger days;
    NSInteger hour;
    NSInteger minutes;
    NSString *durationString;

    components = [[NSCalendar currentCalendar] components: NSCalendarUnitDay|NSCalendarUnitHour|NSCalendarUnitMinute
                                                 fromDate: startDate toDate: endDate options: 0];
    days = [components day];
    hour = [components hour];
    minutes = [components minute];

    if (days > 0) {

        if (days > 1) {
            durationString = [NSString stringWithFormat:@"%d days", days];
        }
        else {
            durationString = [NSString stringWithFormat:@"%d day", days];
        }
        return durationString;
    }

    if (hour > 0) {

        if (hour > 1) {
            durationString = [NSString stringWithFormat:@"%d hours", hour];
        }
        else {
            durationString = [NSString stringWithFormat:@"%d hour", hour];
        }
        return durationString;
    }

    if (minutes > 0) {

        if (minutes > 1) {
            durationString = [NSString stringWithFormat:@"%d minutes", minutes];
        }
        else {
            durationString = [NSString stringWithFormat:@"%d minute", minutes];
        }
        return durationString;
    }

    return @"";
}

Answer 3

Para aquellos que usan swift 3 y superior,

    let dateString1 = "2018-03-15T14:20:00.000Z"
    let dateString2 = "2018-03-20T14:20:00.000Z"

    let Dateformatter = DateFormatter()
    Dateformatter.dateFormat = "yyyy-MM-dd''T''HH:mm:ss.SSSZ"

    let date1 = Dateformatter.date(from: dateString1)
    let date2 = Dateformatter.date(from: dateString2)

    let distanceBetweenDates: TimeInterval? = date2?.timeIntervalSince(date1!)
    let secondsInAnHour: Double = 3600
    let secondsInDays: Double = 86400
    let secondsInWeek: Double = 604800

    let hoursBetweenDates = Int((distanceBetweenDates! / secondsInAnHour))
    let daysBetweenDates = Int((distanceBetweenDates! / secondsInDays))
    let weekBetweenDates = Int((distanceBetweenDates! / secondsInWeek))

    print(weekBetweenDates,"weeks")//0 weeks
    print(daysBetweenDates,"days")//5 days
    print(hoursBetweenDates,"hours")//120 hours

Answer 4

-(NSMutableString*) timeLeftSinceDate: (NSDate *) dateT {

    NSMutableString *timeLeft = [[NSMutableString alloc]init];

    NSDate *today10am =[NSDate date];

    NSInteger seconds = [today10am timeIntervalSinceDate:dateT];

    NSInteger days = (int) (floor(seconds / (3600 * 24)));
    if(days) seconds -= days * 3600 * 24;

    NSInteger hours = (int) (floor(seconds / 3600));
    if(hours) seconds -= hours * 3600;

    NSInteger minutes = (int) (floor(seconds / 60));
    if(minutes) seconds -= minutes * 60;

    if(days) {
        [timeLeft appendString:[NSString stringWithFormat:@"%ld Days", (long)days*-1]];
    }

    if(hours) {
        [timeLeft appendString:[NSString stringWithFormat: @"%ld H", (long)hours*-1]];
    }

    if(minutes) {
        [timeLeft appendString: [NSString stringWithFormat: @"%ld M",(long)minutes*-1]];
    }

    if(seconds) {
        [timeLeft appendString:[NSString stringWithFormat: @"%lds", (long)seconds*-1]];
    }

    return timeLeft;
}

Answer 5

NSCalendar *c = [NSCalendar currentCalendar];
NSDate *d1 = [NSDate date];
NSDate *d2 = [NSDate dateWithTimeIntervalSince1970:1340323201];//2012-06-22
NSDateComponents *components = [c components:NSHourCalendarUnit fromDate:d2 toDate:d1 options:0];
NSInteger diff = components.minute;

NSDayCalendarUnit|NSHourCalendarUnit|NSMinuteCalendarUnit

Cambie los componentes necesarios por día, hora o minuto, qué diferencia desea. Si se selecciona NSDayCalendarUnit , devolverá el número de días entre dos fechas de forma similar para NSHourCalendarUnit y NSMinuteCalendarUnit

Swift 4 versión

let cal = Calendar.current
let d1 = Date()
let d2 = Date.init(timeIntervalSince1970: 1524787200) // April 27, 2018 12:00:00 AM
let components = cal.dateComponents([.hour], from: d2, to: d1)
let diff = components.hour!