tsql - persona - Cómo calcular la edad en T-SQL con años, meses y días

calcular meses entre dos fechas sql server

Question

¿Cuál sería la mejor manera de calcular la edad de alguien en años, meses y días en T-SQL (SQL Server 2000)?

La función de datediff no maneja bien los límites de los años, además de obtener meses y días separados será un oso. Sé que puedo hacerlo por el lado del cliente con relativa facilidad, pero me gustaría que se haga en mi procedimiento almacenado .

Answer 1

Implementado por aritmética con fecha de formato ISO.

declare @now date,@dob date, @now_i int,@dob_i int, @days_in_birth_month int
declare @years int, @months int, @days int
set @now = ''2013-02-28''
set @dob = ''2012-02-29'' -- Date of Birth
set @now_i = convert(varchar(8),@now,112) -- iso formatted: 20130228
set @dob_i = convert(varchar(8),@dob,112) -- iso formatted: 20120229
set @years = ( @now_i - @dob_i)/10000
-- (20130228 - 20120229)/10000 = 0 years
set @months =(1200 + (month(@now)- month(@dob))*100 + day(@now) - day(@dob))/100 %12
-- (1200 + 0228 - 0229)/100 % 12 = 11 months
set @days_in_birth_month = day(dateadd(d,-1,left(convert(varchar(8),dateadd(m,1,@dob),112),6)+''01''))
set @days = (sign(day(@now) - day(@dob))+1)/2 * (day(@now) - day(@dob))
+ (sign(day(@dob) - day(@now))+1)/2 * (@days_in_birth_month - day(@dob) + day(@now))
-- ( (-1+1)/2*(28 - 29) + (1+1)/2*(29 - 29 + 28))
-- Explain: if the days of now is bigger than the days of birth, then diff the two days
-- else add the days of now and the distance from the date of birth to the end of the birth month
select @years,@months,@days -- 0, 11, 28

Casos de prueba

El enfoque de los días es diferente de la respuesta aceptada, las diferencias que se muestran en los comentarios a continuación:

 dob now years months days
2012-02-29 2013-02-28 0 11 28 --Days will be 30 if calculated by the approach in accepted answer.
2012-02-29 2016-02-28 3 11 28 --Days will be 31 if calculated by the approach in accepted answer, since the day of birth will be changed to 28 from 29 after dateadd by years.
2012-02-29 2016-03-31 4 1 2
2012-01-30 2016-02-29 4 0 30
2012-01-30 2016-03-01 4 1 2 --Days will be 1 if calculated by the approach in accepted answer, since the day of birth will be changed to 30 from 29 after dateadd by years.
2011-12-30 2016-02-29 4 1 30

Una versión corta de Days by case statement:

set @days = CASE WHEN day(@now) >= day(@dob) THEN day(@now) - day(@dob)
ELSE @days_in_birth_month - day(@dob) + day(@now) END

Si desea la edad de años y meses solamente, podría ser más simple

set @years = ( @now_i/100 - @dob_i/100)/100
set @months =(12 + month(@now) - month(@dob))%12
select @years,@months -- 1, 0

NOTA: Un enlace muy útil de formatos de fecha de SQL Server

Answer 2

¿Estás tratando de calcular el total de días / meses / años de una edad? ¿tienes una fecha de inicio? ¿O está tratando de diseccionarlo (ej: 24 años, 1 mes, 29 días)?

Si tiene una fecha de inicio con la que está trabajando, datediff mostrará el total de días / meses / años con los siguientes comandos:

Select DateDiff(d,''1984-07-12'',''2008-09-11'')
Select DateDiff(m,''1984-07-12'',''2008-09-11'')
Select DateDiff(yyyy,''1984-07-12'',''2008-09-11'')

con las salidas respectivas (8827/290/24).

Ahora, si quisieras hacer el método de disección, tendrías que restar el número de años en días (días - 365 * años), y luego hacer más cálculos sobre eso para obtener los meses, etc.

Answer 3

Aquí está el código SQL que le da la cantidad de años, meses y días desde sysdate. Ingrese el valor para input_birth_date este formato (dd_mon_aa). nota: ingrese el mismo valor (fecha de nacimiento) por años, meses y días, como 01-mar-85

select trunc((sysdate -to_date(''&input_birth_date_dd_mon_yy''))/365) years,
trunc(mod(( sysdate -to_date(''&input_birth_date_dd_mon_yy''))/365,1)*12) months,
trunc((mod((mod((sysdate -to_date(''&input_birth_date_dd_mon_yy''))/365,1)*12),1)*30)+1) days
from dual

Answer 4

Aquí hay algunos T-SQL que le dan la cantidad de años, meses y días desde el día especificado en @date. Tiene en cuenta el hecho de que DATEDIFF () calcula la diferencia sin considerar qué mes o día es (por lo que el mes difiere entre 8/31 y 9/1 es 1 mes) y maneja eso con una declaración de caso que disminuye el resultado donde apropiado.

DECLARE @date datetime, @tmpdate datetime, @years int, @months int, @days int
SELECT @date = ''2/29/04''
SELECT @tmpdate = @date
SELECT @years = DATEDIFF(yy, @tmpdate, GETDATE()) - CASE WHEN (MONTH(@date) > MONTH(GETDATE())) OR (MONTH(@date) = MONTH(GETDATE()) AND DAY(@date) > DAY(GETDATE())) THEN 1 ELSE 0 END
SELECT @tmpdate = DATEADD(yy, @years, @tmpdate)
SELECT @months = DATEDIFF(m, @tmpdate, GETDATE()) - CASE WHEN DAY(@date) > DAY(GETDATE()) THEN 1 ELSE 0 END
SELECT @tmpdate = DATEADD(m, @months, @tmpdate)
SELECT @days = DATEDIFF(d, @tmpdate, GETDATE())
SELECT @years, @months, @days

Answer 5

Aquí hay una versión (un poco) más simple:

CREATE PROCEDURE dbo.CalculateAge
@dayOfBirth datetime
AS
DECLARE @today datetime, @thisYearBirthDay datetime
DECLARE @years int, @months int, @days int
SELECT @today = GETDATE()
SELECT @thisYearBirthDay = DATEADD(year, DATEDIFF(year, @dayOfBirth, @today), @dayOfBirth)
SELECT @years = DATEDIFF(year, @dayOfBirth, @today) - (CASE WHEN @thisYearBirthDay > @today THEN 1 ELSE 0 END)
SELECT @months = MONTH(@today - @thisYearBirthDay) - 1
SELECT @days = DAY(@today - @thisYearBirthDay) - 1
SELECT @years, @months, @days
GO

Answer 6

Así es como calculo la edad dada una fecha de nacimiento y la fecha actual.

select case
when cast(getdate() as date) = cast(dateadd(year, (datediff(year, ''1996-09-09'', getdate())), ''1996-09-09'') as date)
then dateDiff(yyyy,''1996-09-09'',dateadd(year, 0, getdate()))
else dateDiff(yyyy,''1996-09-09'',dateadd(year, -1, getdate()))
end as MemberAge
go

Answer 7

El mismo tipo de cosa que una función.

create function [dbo].[Age](@dayOfBirth datetime, @today datetime)
RETURNS varchar(100)
AS
Begin
DECLARE @thisYearBirthDay datetime
DECLARE @years int, @months int, @days int
set @thisYearBirthDay = DATEADD(year, DATEDIFF(year, @dayOfBirth, @today), @dayOfBirth)
set @years = DATEDIFF(year, @dayOfBirth, @today) - (CASE WHEN @thisYearBirthDay > @today THEN 1 ELSE 0 END)
set @months = MONTH(@today - @thisYearBirthDay) - 1
set @days = DAY(@today - @thisYearBirthDay) - 1
return cast(@years as varchar(2)) + '' years,'' + cast(@months as varchar(2)) + '' months,'' + cast(@days as varchar(3)) + '' days''
end

Answer 8

Hay una manera fácil, basada en las horas entre los dos días, PERO con la fecha de finalización truncada.

SELECT CAST(DATEDIFF(hour,Birthdate,CAST(GETDATE() as Date))/8766.0 as INT) AS Age FROM <YourTable>

Este ha demostrado ser extremadamente preciso y confiable. Si no fuera por el CAST interno en el GETDATE (), podría voltear el cumpleaños unas horas antes de la medianoche pero, con el CAST, está muerto con el cambio de edad exactamente a la medianoche.

Answer 9

He visto la pregunta varias veces con resultados que arrojan resultados de años, meses, días pero nunca un resultado numérico / decimal. (Al menos no uno que no se redondea incorrectamente). Agradezco los comentarios sobre esta función. Puede que aún no necesite un poco de ajuste.

- La entrada a la función es de dos fechas. - Salida es el número numérico de años entre las dos fechas en formato decimal (7,4). - La salida siempre es siempre un número positivo.

- NOTA: La salida no se maneja si la diferencia es mayor que 999.9999

- La lógica se basa en tres pasos. - 1) Es la diferencia de menos de 1 año (0.5000, 0.3333, 0.6667, etc.) - 2) Es la diferencia exactamente un número entero de años (1,2,3, etc.)

- 3) (Else) ... La diferencia es años y algunos días. (1.5000, 2.3333, 7.6667, etc.)

CREATE Function [dbo].[F_Get_Actual_Age](@pi_date1 datetime,@pi_date2 datetime)
RETURNS Numeric(7,4)
AS
BEGIN
Declare
@l_tmp_date DATETIME
,@l_days1 DECIMAL(9,6)
,@l_days2 DECIMAL(9,6)
,@l_result DECIMAL(10,6)
,@l_years DECIMAL(7,4)
--Check to make sure there is a date for both inputs
IF @pi_date1 IS NOT NULL and @pi_date2 IS NOT NULL
BEGIN
IF @pi_date1 > @pi_date2 --Make sure the "older" date is in @pi_date1
BEGIN
SET @l_tmp_date = @pi_date2
SET @pi_date2 = @Pi_date1
SET @pi_date1 = @l_tmp_date
END
--Check #1 If date1 + 1 year is greater than date2, difference must be less than 1 year
IF DATEADD(YYYY,1,@pi_date1) > @pi_date2
BEGIN
--How many days between the two dates (numerator)
SET @l_days1 = DATEDIFF(dd,@pi_date1, @pi_date2)
--subtract 1 year from date2 and calculate days bewteen it and date2
--This is to get the denominator and accounts for leap year (365 or 366 days)
SET @l_days2 = DATEDIFF(dd,dateadd(yyyy,-1,@pi_date2),@pi_date2)
SET @l_years = @l_days1 / @l_days2 -- Do the math
END
ELSE
--Check #2 Are the dates an exact number of years apart.
--Calculate years bewteen date1 and date2, then add the years to date1, compare dates to see if exactly the same.
IF DATEADD(YYYY,DATEDIFF(YYYY,@pi_date1,@pi_date2),@pi_date1) = @pi_date2
SET @l_years = DATEDIFF(YYYY,@pi_date1, @pi_date2) --AS Years, ''Exactly even Years'' AS Msg
ELSE
BEGIN
--Check #3 The rest of the cases.
--Check if datediff, returning years, over or under states the years difference
SET @l_years = DATEDIFF(YYYY,@pi_date1, @pi_date2)
IF DATEADD(YYYY,@l_years,@pi_date1) > @pi_date2
SET @l_years = @l_years -1
--use basicly same logic as in check #1
SET @l_days1 = DATEDIFF(dd,DATEADD(YYYY,@l_years,@pi_date1), @pi_date2)
SET @l_days2 = DATEDIFF(dd,dateadd(yyyy,-1,@pi_date2),@pi_date2)
SET @l_years = @l_years + @l_days1 / @l_days2
--SELECT @l_years AS Years, ''Years Plus'' AS Msg
END
END
ELSE
SET @l_years = 0 --If either date was null
RETURN @l_Years --Return the result as decimal(7,4)
END

`

Answer 10

Muy vieja pregunta, pero quiero compartir lo que he hecho para calcular la edad

 Declare @BirthDate As DateTime
Set @BirthDate = ''1994-11-02''
SELECT DATEDIFF(YEAR,@BirthDate,GETDATE()) - (CASE
WHEN MONTH(@BirthDate)> MONTH(GETDATE()) THEN 1
WHEN MONTH(@BirthDate)= MONTH(GETDATE()) AND DAY(@BirthDate) > DAY(GETDATE()) THEN 1
Else 0 END)

Answer 11

Para los que quieren crear una columna calculada en una tabla para almacenar la edad:

CASE WHEN DateOfBirth< DATEADD(YEAR, (DATEPART(YEAR, GETDATE()) - DATEPART(YEAR, DateOfBirth))*-1, GETDATE())
THEN DATEPART(YEAR, GETDATE()) - DATEPART(YEAR, DateOfBirth)
ELSE DATEPART(YEAR, GETDATE()) - DATEPART(YEAR, DateOfBirth) -1 END

Answer 12

Prueba esto...

SELECT CASE WHEN
(DATEADD(year,DATEDIFF(year, @datestart ,@dateend) , @datestart) > @dateend)
THEN DATEDIFF(year, @datestart ,@dateend) -1
ELSE DATEDIFF(year, @datestart ,@dateend)
END

Básicamente, el "DateDiff (año ...") te da la edad que la persona cumplirá este año, así que acabo de agregar un enunciado de caso para decir, si aún no han celebrado un cumpleaños este año, luego restar 1 año, sino devuelve el valor

Answer 13

Una manera simple de obtener la edad como texto es la siguiente:

Select cast((DATEDIFF(m, date_of_birth, GETDATE())/12) as varchar) + '' Y & '' +
cast((DATEDIFF(m, date_of_birth, GETDATE())%12) as varchar) + '' M'' as Age

El formato de resultados será:

**63 Y & 2 M**

Answer 14

DateTime valores de DateTime en T-SQL se almacenan como flotantes. Puede restar las fechas entre sí y ahora tiene una nueva fecha que es el intervalo de tiempo entre ellas.

declare @birthdate datetime
set @birthdate = ''6/15/1974''
--age in years - short version
print year(getdate() - @birthdate) - year(0)
--age in years - visualization
declare @mindate datetime
declare @span datetime
set @mindate = 0
set @span = getdate() - @birthdate
print @mindate
print @birthdate
print getdate()
print @span
--substract minyear from spanyear to get age in years
print year(@span) - year(@mindate)
print month(@span)
print day(@span)

Answer 15

CREATE FUNCTION DBO.GET_AGE
(
@DATE AS DATETIME
)
RETURNS VARCHAR(MAX)
AS
BEGIN
DECLARE @YEAR AS VARCHAR(50) = ''''
DECLARE @MONTH AS VARCHAR(50) = ''''
DECLARE @DAYS AS VARCHAR(50) = ''''
DECLARE @RESULT AS VARCHAR(MAX) = ''''
SET @YEAR = CONVERT(VARCHAR,(SELECT DATEDIFF(MONTH,CASE WHEN DAY(@DATE) > DAY(GETDATE()) THEN DATEADD(MONTH,1,@DATE) ELSE @DATE END,GETDATE()) / 12 ))
SET @MONTH = CONVERT(VARCHAR,(SELECT DATEDIFF(MONTH,CASE WHEN DAY(@DATE) > DAY(GETDATE()) THEN DATEADD(MONTH,1,@DATE) ELSE @DATE END,GETDATE()) % 12 ))
SET @DAYS = DATEDIFF(DD,DATEADD(MM,CONVERT(INT,CONVERT(INT,@YEAR)*12 + CONVERT(INT,@MONTH)),@DATE),GETDATE())
SET @RESULT = (RIGHT(''00'' + @YEAR, 2) + '' YEARS '' + RIGHT(''00'' + @MONTH, 2) + '' MONTHS '' + RIGHT(''00'' + @DAYS, 2) + '' DAYS'')
RETURN @RESULT
END
SELECT DBO.GET_AGE(''04/12/1986'')

Answer 16

DECLARE @BirthDate datetime, @AgeInMonths int
SET @BirthDate = ''10/5/1971''
SET @AgeInMonths -- Determine the age in "months old":
= DATEDIFF(MONTH, @BirthDate, GETDATE()) -- .Get the difference in months
- CASE WHEN DATEPART(DAY,GETDATE()) -- .If today was the 1st to 4th,
< DATEPART(DAY,@BirthDate) -- (or before the birth day of month)
THEN 1 ELSE 0 END -- ... don''t count the month.
SELECT @AgeInMonths / 12 as AgeYrs -- Divide by 12 months to get the age in years
,@AgeInMonths % 12 as AgeXtraMonths -- Get the remainder of dividing by 12 months = extra months
,DATEDIFF(DAY -- For the extra days, find the difference between,
,DATEADD(MONTH, @AgeInMonths -- 1. Last Monthly Birthday
, @BirthDate) -- (if birthdays were celebrated monthly)
,GETDATE()) as AgeXtraDays -- 2. Today''s date.

Answer 17

DECLARE @DoB AS DATE = ''1968-10-24''
DECLARE @cDate AS DATE = CAST(''2000-10-23'' AS DATE)
SELECT
--Get Year difference
DATEDIFF(YEAR,@DoB,@cDate) -
--Cases where year difference will be augmented
CASE
--If Date of Birth greater than date passed return 0
WHEN YEAR(@DoB) - YEAR(@cDate) >= 0 THEN DATEDIFF(YEAR,@DoB,@cDate)
--If date of birth month less than date passed subtract one year
WHEN MONTH(@DoB) - MONTH(@cDate) > 0 THEN 1
--If date of birth day less than date passed subtract one year
WHEN MONTH(@DoB) - MONTH(@cDate) = 0 AND DAY(@DoB) - DAY(@cDate) > 0 THEN 1
--All cases passed subtract zero
ELSE 0
END

Answer 18

SELECT DOB AS Birthdate ,
YEAR(GETDATE()) AS ThisYear,
YEAR(getdate()) - YEAR(DOB) AS Age
FROM tableprincejain

Answer 19

create procedure getDatedifference
(
@startdate datetime,
@enddate datetime
)
as
begin
declare @monthToShow int
declare @dayToShow int
--set @startdate=''01/21/1934''
--set @enddate=getdate()
if (DAY(@startdate) > DAY(@enddate))
begin
set @dayToShow=0
if (month(@startdate) > month(@enddate))
begin
set @monthToShow= (12-month(@startdate)+ month(@enddate)-1)
end
else if (month(@startdate) < month(@enddate))
begin
set @monthToShow= ((month(@enddate)-month(@startdate))-1)
end
else
begin
set @monthToShow= 11
end
-- set @monthToShow= convert(int, DATEDIFF(mm,0,DATEADD(dd,DATEDIFF(dd,0,@enddate)- DATEDIFF(dd,0,@startdate),0)))-((convert(int,FLOOR(DATEDIFF(day, @startdate, @enddate) / 365.25))*12))-1
if(@monthToShow<0)
begin
set @monthToShow=0
end
declare @amonthbefore integer
set @amonthbefore=Month(@enddate)-1
if(@amonthbefore=0)
begin
set @amonthbefore=12
end
if (@amonthbefore in(1,3,5,7,8,10,12))
begin
set @dayToShow=31-DAY(@startdate)+DAY(@enddate)
end
if (@amonthbefore=2)
begin
IF (YEAR( @enddate ) % 4 = 0 AND YEAR( @enddate ) % 100 != 0) OR YEAR( @enddate ) % 400 = 0
begin
set @dayToShow=29-DAY(@startdate)+DAY(@enddate)
end
else
begin
set @dayToShow=28-DAY(@startdate)+DAY(@enddate)
end
end
if (@amonthbefore in (4,6,9,11))
begin
set @dayToShow=30-DAY(@startdate)+DAY(@enddate)
end
end
else
begin
--set @monthToShow=convert(int, DATEDIFF(mm,0,DATEADD(dd,DATEDIFF(dd,0,@enddate)- DATEDIFF(dd,0,@startdate),0)))-((convert(int,FLOOR(DATEDIFF(day, @startdate, @enddate) / 365.25))*12))
if (month(@enddate)< month(@startdate))
begin
set @monthToShow=12+(month(@enddate)-month(@startdate))
end
else
begin
set @monthToShow= (month(@enddate)-month(@startdate))
end
set @dayToShow=DAY(@enddate)-DAY(@startdate)
end
SELECT
FLOOR(DATEDIFF(day, @startdate, @enddate) / 365.25) as [yearToShow],
@monthToShow as monthToShow ,@dayToShow as dayToShow ,
convert(varchar,FLOOR(DATEDIFF(day, @startdate, @enddate) / 365.25)) +'' Year '' + convert(varchar,@monthToShow) +'' months ''+convert(varchar,@dayToShow)+'' days '' as age
return
end

Answer 20

declare @StartDate datetime = ''2016-01-31''
declare @EndDate datetime = ''2016-02-01''
SELECT @StartDate AS [StartDate]
,@EndDate AS [EndDate]
,DATEDIFF(Year,@StartDate,@EndDate) - CASE WHEN DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate), @StartDate) > @EndDate THEN 1 ELSE 0 END AS [Years]
,DATEDIFF(Month,(DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate) - CASE WHEN DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate), @StartDate) > @EndDate THEN 1 ELSE 0 END,@StartDate)),@EndDate) - CASE WHEN DATEADD(Month, DATEDIFF(Month,DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate) - CASE WHEN DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate), @StartDate) > @EndDate THEN 1 ELSE 0 END,@StartDate),@EndDate) , @StartDate) > @EndDate THEN 1 ELSE 0 END AS [Months]
,DATEDIFF(Day, DATEADD(Month,DATEDIFF(Month, (DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate) - CASE WHEN DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate), @StartDate) > @EndDate THEN 1 ELSE 0 END,@StartDate)),@EndDate) - CASE WHEN DATEADD(Month, DATEDIFF(Month,DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate) - CASE WHEN DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate), @StartDate) > @EndDate THEN 1 ELSE 0 END,@StartDate),@EndDate) , @StartDate) > @EndDate THEN 1 ELSE 0 END ,DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate) - CASE WHEN DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate), @StartDate) > @EndDate THEN 1 ELSE 0 END,@StartDate)) ,@EndDate) - CASE WHEN DATEADD(Day,DATEDIFF(Day, DATEADD(Month,DATEDIFF(Month, (DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate) - CASE WHEN DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate), @StartDate) > @EndDate THEN 1 ELSE 0 END,@StartDate)),@EndDate) - CASE WHEN DATEADD(Month, DATEDIFF(Month,DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate) - CASE WHEN DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate), @StartDate) > @EndDate THEN 1 ELSE 0 END,@StartDate),@EndDate) , @StartDate) > @EndDate THEN 1 ELSE 0 END ,DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate) - CASE WHEN DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate), @StartDate) > @EndDate THEN 1 ELSE 0 END,@StartDate)) ,@EndDate),DATEADD(Month,DATEDIFF(Month, (DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate) - CASE WHEN DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate), @StartDate) > @EndDate THEN 1 ELSE 0 END,@StartDate)),@EndDate) - CASE WHEN DATEADD(Month, DATEDIFF(Month,DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate) - CASE WHEN DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate), @StartDate) > @EndDate THEN 1 ELSE 0 END,@StartDate),@EndDate) , @StartDate) > @EndDate THEN 1 ELSE 0 END ,DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate) - CASE WHEN DATEADD(Year,DATEDIFF(Year,@StartDate,@EndDate), @StartDate) > @EndDate THEN 1 ELSE 0 END,@StartDate))) > @EndDate THEN 1 ELSE 0 END AS [Days]

Answer 21

select DOB as Birthdate,
YEAR(GETDATE()) as ThisYear,
YEAR(getdate()) - EAR(date1) as Age
from TableName