Str al tiempo en Python

datetime strptime

Question

time1 = "2010-04-20 10:07:30"
time2 = "2010-04-21 10:07:30"

¿Cómo convertir lo anterior de cadena a marca de tiempo?

Necesito restar las marcas de tiempo anteriores time2-time1 .

Answer 1

Para Python 2.5+

from datetime import datetime
format = ''%Y-%m-%d %H:%M:%S''
print datetime.strptime(time2, format) - 
        datetime.strptime(time1, format)
# 1 day, 0:00:00

Edición: para Python 2.4

import time
format = ''%Y-%m-%d %H:%M:%S''
print time.mktime(time.strptime(time2, format)) - 
        time.mktime(time.strptime(time1, format))
# 86400.0

Answer 2

Si estás atrapado en el sistema Python 2.4 como yo:

from time import strptime
from datetime import datetime

str_to_datetime = lambda st: datetime(*strptime(st, ''%Y-%m-%d %H:%M:%S'')[:6])

str_to_datetime(''2010-04-20 10:07:30'')

De lo contrario, datetime.strptime () funcionará bien.

Answer 3

import time

time1 = "2010-04-20 10:07:30"

time_tuple = time.strptime(time1, "%Y-%m-%d %H:%M:%S")

timestamp = time.mktime(time_tuple)

Answer 4

>>> t1 = datetime.strptime(time1, "%Y-%m-%d %H:%M:%S")
>>> t2 = datetime.strptime(time2, "%Y-%m-%d %H:%M:%S")
>>> t2-t1
datetime.timedelta(1)

>>> (t2-t1).days
1
>>> (t2-t1).seconds
0