vacio - eliminar na en r

Reste cada elemento del vector A de cada elemento del vector B

Question

¿Alguien sabe alguna forma de lograr lo siguiente en un formato vectorizado?

En lugar de restar test1 de miembro a test , me gustaría restar cada elemento de test1 de cada elemento de test . Entonces, en lugar de:

test = c(1:10)
test1 = seq(0.1, 1, 0.1)
test - test1
[1] 0.9 1.8 2.7 3.6 4.5 5.4 6.3 7.2 8.1 9.0

Yo quiero:

test2=vector("list")
for(i in 1:length(test)){
test2[[i]] = test[i] - test1
}
test2
[[1]]
[1] 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0.0
[[2]]
[1] 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1.0
[[3]]
[1] 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0
[[4]]
[1] 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0
[[5]]
[1] 4.9 4.8 4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0
[[6]]
[1] 5.9 5.8 5.7 5.6 5.5 5.4 5.3 5.2 5.1 5.0
[[7]]
[1] 6.9 6.8 6.7 6.6 6.5 6.4 6.3 6.2 6.1 6.0
[[8]]
[1] 7.9 7.8 7.7 7.6 7.5 7.4 7.3 7.2 7.1 7.0
[[9]]
[1] 8.9 8.8 8.7 8.6 8.5 8.4 8.3 8.2 8.1 8.0
[[10]]
[1] 9.9 9.8 9.7 9.6 9.5 9.4 9.3 9.2 9.1 9.0

Incluso para vectores de longitud desigual?

Answer 1

Esto hace el truco:

lapply(test,function(x) x - test1)

Answer 2

Un enfoque vectorizado que le da la lista deseada:

x = rep(test, each=length(test))
split(x- test1, x)
#$`1`
# [1] 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0.0
#$`2`
# [1] 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1.0
#$`3`
# [1] 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0
#$`4`
# [1] 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0
#$`5`
# [1] 4.9 4.8 4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0
#$`6`
# [1] 5.9 5.8 5.7 5.6 5.5 5.4 5.3 5.2 5.1 5.0
#$`7`
# [1] 6.9 6.8 6.7 6.6 6.5 6.4 6.3 6.2 6.1 6.0
#$`8`
# [1] 7.9 7.8 7.7 7.6 7.5 7.4 7.3 7.2 7.1 7.0
#$`9`
# [1] 8.9 8.8 8.7 8.6 8.5 8.4 8.3 8.2 8.1 8.0
#$`10`
# [1] 9.9 9.8 9.7 9.6 9.5 9.4 9.3 9.2 9.1 9.0

Answer 3

outer(test, test1, `-`)
# [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
# [1,] 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0
# [2,] 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1
# [3,] 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2
# [4,] 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3
# [5,] 4.9 4.8 4.7 4.6 4.5 4.4 4.3 4.2 4.1 4
# [6,] 5.9 5.8 5.7 5.6 5.5 5.4 5.3 5.2 5.1 5
# [7,] 6.9 6.8 6.7 6.6 6.5 6.4 6.3 6.2 6.1 6
# [8,] 7.9 7.8 7.7 7.6 7.5 7.4 7.3 7.2 7.1 7
# [9,] 8.9 8.8 8.7 8.6 8.5 8.4 8.3 8.2 8.1 8
# [10,] 9.9 9.8 9.7 9.6 9.5 9.4 9.3 9.2 9.1 9

Answer 4

> test = c(1:10)
> test1 = seq(0.1, 1, 0.1)
> lapply(test,function(e) e-test1)
[[1]]
[1] 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0.0
[[2]]
[1] 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1.0
[[3]]
[1] 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0
[[4]]
[1] 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0
[[5]]
[1] 4.9 4.8 4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0
[[6]]
[1] 5.9 5.8 5.7 5.6 5.5 5.4 5.3 5.2 5.1 5.0
[[7]]
[1] 6.9 6.8 6.7 6.6 6.5 6.4 6.3 6.2 6.1 6.0
[[8]]
[1] 7.9 7.8 7.7 7.6 7.5 7.4 7.3 7.2 7.1 7.0
[[9]]
[1] 8.9 8.8 8.7 8.6 8.5 8.4 8.3 8.2 8.1 8.0
[[10]]
[1] 9.9 9.8 9.7 9.6 9.5 9.4 9.3 9.2 9.1 9.0