python - example - Subproceso.Pobular: clonación de stdout y stderr tanto para el terminal como para las variables

subprocess python español

Question

¿Es posible modificar el código a continuación para tener una impresión de ''stdout'' y ''stderr''?

• impreso en la terminal (en tiempo real),
• y finalmente se almacena en las variables outs y errs ?

El código:

#!/usr/bin/python3
# -*- coding: utf-8 -*-
import subprocess
def run_cmd(command, cwd=None):
p = subprocess.Popen(command, cwd=cwd, shell=False,
stdout=subprocess.PIPE,
stderr=subprocess.PIPE)
outs, errs = p.communicate()
rc = p.returncode
outs = outs.decode(''utf-8'')
errs = errs.decode(''utf-8'')
return (rc, (outs, errs))

Gracias a @unutbu, gracias especiales para @ jf-sebastian, función final:

#!/usr/bin/python3
# -*- coding: utf-8 -*-
import sys
from queue import Queue
from subprocess import PIPE, Popen
from threading import Thread
def read_output(pipe, funcs):
for line in iter(pipe.readline, b''''):
for func in funcs:
func(line.decode(''utf-8''))
pipe.close()
def write_output(get):
for line in iter(get, None):
sys.stdout.write(line)
def run_cmd(command, cwd=None, passthrough=True):
outs, errs = None, None
proc = Popen(
command,
cwd=cwd,
shell=False,
close_fds=True,
stdout=PIPE,
stderr=PIPE,
bufsize=1
)
if passthrough:
outs, errs = [], []
q = Queue()
stdout_thread = Thread(
target=read_output, args=(proc.stdout, [q.put, outs.append])
)
stderr_thread = Thread(
target=read_output, args=(proc.stderr, [q.put, errs.append])
)
writer_thread = Thread(
target=write_output, args=(q.get,)
)
for t in (stdout_thread, stderr_thread, writer_thread):
t.daemon = True
t.start()
proc.wait()
for t in (stdout_thread, stderr_thread):
t.join()
q.put(None)
outs = '' ''.join(outs)
errs = '' ''.join(errs)
else:
outs, errs = proc.communicate()
outs = '''' if outs == None else outs.decode(''utf-8'')
errs = '''' if errs == None else errs.decode(''utf-8'')
rc = proc.returncode
return (rc, (outs, errs))

Answer 1

Para capturar y visualizar al mismo tiempo tanto stdout como stderr desde un proceso hijo línea por línea en un solo hilo, puede usar E / S asincrónicas:

#!/usr/bin/env python3
import asyncio
import os
import sys
from asyncio.subprocess import PIPE
@asyncio.coroutine
def read_stream_and_display(stream, display):
"""Read from stream line by line until EOF, display, and capture the lines.
"""
output = []
while True:
line = yield from stream.readline()
if not line:
break
output.append(line)
display(line) # assume it doesn''t block
return b''''.join(output)
@asyncio.coroutine
def read_and_display(*cmd):
"""Capture cmd''s stdout, stderr while displaying them as they arrive
(line by line).
"""
# start process
process = yield from asyncio.create_subprocess_exec(*cmd,
stdout=PIPE, stderr=PIPE)
# read child''s stdout/stderr concurrently (capture and display)
try:
stdout, stderr = yield from asyncio.gather(
read_stream_and_display(process.stdout, sys.stdout.buffer.write),
read_stream_and_display(process.stderr, sys.stderr.buffer.write))
except Exception:
process.kill()
raise
finally:
# wait for the process to exit
rc = yield from process.wait()
return rc, stdout, stderr
# run the event loop
if os.name == ''nt'':
loop = asyncio.ProactorEventLoop() # for subprocess'' pipes on Windows
asyncio.set_event_loop(loop)
else:
loop = asyncio.get_event_loop()
rc, *output = loop.run_until_complete(read_and_display(*cmd))
loop.close()

Answer 2

Puede engendrar hilos para leer los tubos stdout y stderr, escribir en una cola común y anexar a las listas. Luego use un tercer hilo para imprimir elementos de la cola.

import time
import Queue
import sys
import threading
import subprocess
PIPE = subprocess.PIPE
def read_output(pipe, funcs):
for line in iter(pipe.readline, ''''):
for func in funcs:
func(line)
# time.sleep(1)
pipe.close()
def write_output(get):
for line in iter(get, None):
sys.stdout.write(line)
process = subprocess.Popen(
[''random_print.py''], stdout=PIPE, stderr=PIPE, close_fds=True, bufsize=1)
q = Queue.Queue()
out, err = [], []
tout = threading.Thread(
target=read_output, args=(process.stdout, [q.put, out.append]))
terr = threading.Thread(
target=read_output, args=(process.stderr, [q.put, err.append]))
twrite = threading.Thread(target=write_output, args=(q.get,))
for t in (tout, terr, twrite):
t.daemon = True
t.start()
process.wait()
for t in (tout, terr):
t.join()
q.put(None)
print(out)
print(err)

La razón para usar el tercer subproceso, en lugar de dejar que los primeros dos subprocesos se impriman directamente en el terminal, es evitar que ambas declaraciones de impresión se produzcan al mismo tiempo, lo que puede dar lugar a un texto a veces confuso.

Lo anterior llama a random_print.py , que imprime a stdout y stderr al azar:

import sys
import time
import random
for i in range(50):
f = random.choice([sys.stdout,sys.stderr])
f.write(str(i)+''/n'')
f.flush()
time.sleep(0.1)

Esta solución toma prestados código e ideas de JF Sebastian, aquí .

Aquí hay una solución alternativa para sistemas tipo Unix, usando select.select :

import collections
import select
import fcntl
import os
import time
import Queue
import sys
import threading
import subprocess
PIPE = subprocess.PIPE
def make_async(fd):
# https://.com/a/7730201/190597
''''''add the O_NONBLOCK flag to a file descriptor''''''
fcntl.fcntl(
fd, fcntl.F_SETFL, fcntl.fcntl(fd, fcntl.F_GETFL) | os.O_NONBLOCK)
def read_async(fd):
# https://.com/a/7730201/190597
''''''read some data from a file descriptor, ignoring EAGAIN errors''''''
# time.sleep(1)
try:
return fd.read()
except IOError, e:
if e.errno != errno.EAGAIN:
raise e
else:
return ''''
def write_output(fds, outmap):
for fd in fds:
line = read_async(fd)
sys.stdout.write(line)
outmap[fd.fileno()].append(line)
process = subprocess.Popen(
[''random_print.py''], stdout=PIPE, stderr=PIPE, close_fds=True)
make_async(process.stdout)
make_async(process.stderr)
outmap = collections.defaultdict(list)
while True:
rlist, wlist, xlist = select.select([process.stdout, process.stderr], [], [])
write_output(rlist, outmap)
if process.poll() is not None:
write_output([process.stdout, process.stderr], outmap)
break
fileno = {''stdout'': process.stdout.fileno(),
''stderr'': process.stderr.fileno()}
print(outmap[fileno[''stdout'']])
print(outmap[fileno[''stderr'']])

Esta solución usa código e ideas de la publicación de Adam Rosenfield, aquí .