java - inner - in criteria in hibernate

Criterios de Hibernate: realizar JOIN en Subquery/DetachedCriteria

Question

Me encuentro con un problema al agregar JOIN a una subconsulta usando DetachedCriteria. El código se ve más o menos así:

Criteria criteria = createCacheableCriteria(ProductLine.class, "productLine");
criteria.add(Expression.eq("productLine.active", "Y"));

DetachedCriteria subCriteria = DetachedCriteria.forClass(Model.class, "model");
subCriteria.setProjection(Projections.rowCount());
subCriteria.createAlias("model.modelLanguages", "modelLang");
subCriteria.createAlias("modelLang.language", "lang");
criteria.add(Expression.eq("lang.langCode", "EN"));
subCriteria.add(Restrictions.eqProperty("model.productLine.productLineId","productLine.productLineId"));
criteria.add(Subqueries.lt(0, subCriteria));

Pero el SQL registrado no contiene el JOIN en la subconsulta, pero sí incluye el alias que arroja un error

SELECT *
FROM PRODUCT_LINE this_
WHERE this_.ACTIVE=?
AND ?                  <
  (SELECT COUNT(*) AS y0_
  FROM MODEL this0__
  WHERE lang3_.LANG_CODE      =''EN''
  AND this0__.PRODUCT_LINE_ID     =this_.ID
  )

¿Cómo puedo agregar las uniones a DetachedCriteria?

@Entity
@Table(name = "PRODUCT_LINE")
public class ProductLine implements java.io.Serializable {

    private long productLineId;
    private char active;
    private Set<Models> models = new HashSet<Models>(0);

    @OneToMany(fetch = FetchType.LAZY, mappedBy = "productLine")
    public Set<Models> getModels() {
        return this.models;
    }

}

@Entity
@Table(name = "MODEL")
public class Model implements java.io.Serializable {

    private long modelId;
    private ProductLine productLine;
    private String name;
    private Set<ModelLanguages> modelLanguages = new HashSet<ModelLanguages>(0);

    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name = "PRODUCT_LINE_ID")
    public ProductLine getProductLine() {
        return this.productLine;
    }

    @Column(name = "NAME", nullable = false)
    public String getName() {
        return this.name;
    }

    @OneToMany(fetch = FetchType.LAZY, mappedBy = "model")
    public Set<ModelLanguages> getModelLanguages() {
        return this.modelLanguages;
    }

}

@Entity
@Table(name = "MODEL_LANGUAGES")
public class ModelLanguages implements java.io.Serializable {

    private long id;
    private Language language;
    private Model model;

    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name = "LANGUAGE_ID", nullable = false, insertable = false, updatable = false)
    public Language getLanguage() {
        return this.language;
    }

    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name = "MODEL_ID", nullable = false, insertable = false, updatable = false)
    public Model getModel() {
        return this.model;
    }
}


@Entity
@Table(name = "LANGUAGES", uniqueConstraints = @UniqueConstraint(columnNames = "LANG_CODE"))
public class Language implements java.io.Serializable {

    private long languageId;
    private String langCode;
    private Set<ModelLanguages> modelLanguages = new HashSet<ModelLanguages>(
            0);

    @Column(name = "LANG_CODE", unique = true, nullable = false)
    public String getLangCode() {
        return this.langCode;
    }

    @OneToMany(fetch = FetchType.LAZY, mappedBy = "language")
    public Set<ModelLanguages> getModelLanguages() {
        return this.modelLanguages;
    }
}

Hibernate version: 3.2.6.ga
Hibernate core: 3.3.2.GA
Hibernate annotations: 3.4.0.GA
Hibernate commons-annotations: 3.3.0.ga
Hibernate entitymanager: 3.4.0.GA
Hibernate validator: 3.1.0.GA

Answer 1

No tienes un error tipográfico en tu código en la siguiente línea:

criteria.add(Expression.eq("lang.langCode", "EN"));

Creo que deberías agregar esta restricción a los subcriterios y no a los criterios.

Answer 2

Si necesita unir tablas en subconsulta, intente hacer esto. Especifica explícitamente joinType en sus criterios separados.

subCriteria.createAlias("model.modelLanguages", "modelLang", CriteriaSpecification.LEFT_JOIN);
subCriteria.createAlias("modelLang.language", "lang", CriteriaSpecification.LEFT_JOIN);