lista - Filtrar objetos javascript con otra matriz

map javascript

Question

Tengo Javascript array de objetos como este

var posts = [
 {area: ''NY'', name: ''Bla'', ads: true},
 {area: ''DF'', name: ''SFS'', ads: false},
 {area: ''TT'', name: ''SDSD'', ads: true},
 {area: ''SD'', name: ''Engine'', ads: false},
 {area: ''NSK'', name: ''Toyota'', ads: false},
];

y otra colección de filtros como esta

var filter = [''NY'', ''SD''];

Estoy tratando de filtrar mi matriz de posts con este filtro

function filtered() {
  return posts
     .filter(function(post){
        return post.ads === true;
     })
     .filter(function(post){
        return filter.indexOf(post.area) > 0;
     })
}

console.log(filtered());

y este filtro no da nada, solo matriz vacía

Por favor revisa jsfiddle

Answer 1

Este es un caso de uso típico para Array.prototype.filter() y Array.prototype.some() combo.

var posts = [
 {area: ''NY'', name: ''Bla'', ads: true},
 {area: ''DF'', name: ''SFS'', ads: false},
 {area: ''TT'', name: ''SDSD'', ads: true},
 {area: ''SD'', name: ''Engine'', ads: false},
 {area: ''NSK'', name: ''Toyota'', ads: false},
],
  filter = [''NY'', ''SD''];
  result = posts.filter(o => filter.some(f => o.ads && f === o.area));
console.log(result);

// or with filter & includes combo

  result = posts.filter(o => o.ads &&  filter.includes(o.area));
console.log(result);

Answer 2

Podría usar una solución más genérica con restricciones para el filtrado.

function filter(array, constraints) {
    return array.filter(function(a) {
        return Object.keys(constraints).every(function(k) {
            return typeof constraints[k] === ''function'' ? constraints[k](a[k]) : a[k] === constraints[k] ;
        });
    });
}

var posts = [{ area: ''NY'', name: ''Bla'', ads: true }, { rea: ''DF'', name: ''SFS'', ads: false }, { area: ''TT'', name: ''SDSD'', ads: true }, { rea: ''SD'', name: ''Engine'', ads: false }, { area: ''NSK'', ame: ''Toyota'', ads: false }],
    result = filter(posts, {
        ads: true,
        area: function (v) { return [''NY'', ''SD''].indexOf(v) !== -1; }
    });

console.log(result);

Answer 3

Solo se necesita Array#filter método de Array#filter único Array#filter y la segunda condición debe ser indexOf(post.area) > -1; ya que el índice comienza desde 0 .

var posts = [
 {area: ''NY'', name: ''Bla'', ads: true},
 {area: ''DF'', name: ''SFS'', ads: false},
 {area: ''TT'', name: ''SDSD'', ads: true},
 {area: ''SD'', name: ''Engine'', ads: false},
 {area: ''NSK'', name: ''Toyota'', ads: false},
];
  
var filter = [''NY'', ''SD''];

function filtered(p, f) {
  return p
    .filter(function(v) {
      return v.ads && f.indexOf(v.area) > -1;
    })
}

console.log(filtered(posts, filter));