listas - sort python 3

Lista de Python ordenada en orden descendente

Question

¿Cómo puedo ordenar esta lista en orden descendente?

timestamp = [
"2010-04-20 10:07:30",
"2010-04-20 10:07:38",
"2010-04-20 10:07:52",
"2010-04-20 10:08:22",
"2010-04-20 10:08:22",
"2010-04-20 10:09:46",
"2010-04-20 10:10:37",
"2010-04-20 10:10:58",
"2010-04-20 10:11:50",
"2010-04-20 10:12:13",
"2010-04-20 10:12:13",
"2010-04-20 10:25:38"
]

Answer 1

En una línea, usando un lambda :

timestamp.sort(key=lambda x: time.strptime(x, ''%Y-%m-%d %H:%M:%S'')[0:6], reverse=True)

Pasando una función a list.sort :

def foo(x):
return time.strptime(x, ''%Y-%m-%d %H:%M:%S'')[0:6]
timestamp.sort(key=foo, reverse=True)

Answer 2

Esto le dará una versión ordenada de la matriz.

sorted(timestamp, reverse=True)

Si desea ordenar en el lugar:

timestamp.sort(reverse=True)

Answer 3

Simplemente puede hacer esto:

timestamp.sort(reverse=True)

Answer 4

Ya que su lista ya está en orden ascendente, simplemente podemos revertir la lista.

>>> timestamp.reverse()
>>> timestamp
[''2010-04-20 10:25:38'',
''2010-04-20 10:12:13'',
''2010-04-20 10:12:13'',
''2010-04-20 10:11:50'',
''2010-04-20 10:10:58'',
''2010-04-20 10:10:37'',
''2010-04-20 10:09:46'',
''2010-04-20 10:08:22'',
''2010-04-20 10:08:22'',
''2010-04-20 10:07:52'',
''2010-04-20 10:07:38'',
''2010-04-20 10:07:30'']

Answer 5

tu tipo simple

timestamp.sort()
timestamp=timestamp[::-1]