python - tutorial - Ya registrado en/appname/: El usuario modelo ya está registrado

register and login django

Question

Estoy intentando conectar el usuario django.contrib.auth con mi propio perfil de usuario, y aparece un error "AlreadyRegistered" cuando estoy en el sitio.

Aquí está el rastreo:

Environment:


Request Method: GET
Request URL: myurl.com/django/appname/

Django Version: 1.4.2
Python Version: 2.6.8
Installed Applications:
(''django.contrib.auth'',
 ''django.contrib.contenttypes'',
 ''django.contrib.sessions'',
 ''django.contrib.sites'',
 ''django.contrib.messages'',
 ''django.contrib.staticfiles'',
 ''django.contrib.admin'',
 ''polls'',
 ''appname'',
 ''registration'',
 ''django.contrib.humanize'')
Installed Middleware:
(''django.middleware.common.CommonMiddleware'',
 ''django.contrib.sessions.middleware.SessionMiddleware'',
 ''django.middleware.csrf.CsrfViewMiddleware'',
 ''django.contrib.auth.middleware.AuthenticationMiddleware'',
 ''django.contrib.messages.middleware.MessageMiddleware'')


Traceback:
File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py" in get_response
  101.                             request.path_info)
File "/usr/lib/python2.6/site-packages/django/core/urlresolvers.py" in resolve
  298.             for pattern in self.url_patterns:
File "/usr/lib/python2.6/site-packages/django/core/urlresolvers.py" in url_patterns
  328.         patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)
File "/usr/lib/python2.6/site-packages/django/core/urlresolvers.py" in urlconf_module
  323.             self._urlconf_module = import_module(self.urlconf_name)
File "/usr/lib/python2.6/site-packages/django/utils/importlib.py" in import_module
  35.     __import__(name)
File "/var/www/mysite/mysite/urls.py" in <module>
  3. admin.autodiscover()
File "/usr/lib/python2.6/site-packages/django/contrib/admin/__init__.py" in autodiscover
  29.             import_module(''%s.admin'' % app)
File "/usr/lib/python2.6/site-packages/django/utils/importlib.py" in import_module
  35.     __import__(name)
File "/var/www/mysite/appname/admin.py" in <module>
  4. admin.site.register(User)
File "/usr/lib/python2.6/site-packages/django/contrib/admin/sites.py" in register
  80.                 raise AlreadyRegistered(''The model %s is already registered'' % model.__name__)

Exception Type: AlreadyRegistered at /appname/
Exception Value: The model User is already registered

Estoy bastante seguro de que esto se debe a los modelos.py de mi aplicación, ya que creo que eso es todo lo que he cambiado de manera importante.

from django.db import models
from django.contrib.auth.models import User
from django.db.models.signals import post_save

class Tag(models.Model):
        pics = models.ManyToManyField(''Picture'', blank=True)
        name = models.CharField(max_length=30)

        def __unicode__(self):
                return self.name

class UserProfile(models.Model):
        name = models.CharField(max_length=20)
        date_joined = models.DateTimeField(''date joined'')
        auth_user = models.OneToOneField(User)

        def __unicode__(self):
                return self.name

def create_user_profile(sender, instance, created, **kwargs):
        if created:
                UserProfile.objects.create(user=instance)

post_save.connect(create_user_profile, sender=User)

class Picture(models.Model):
        name = models.CharField(max_length=100)
        pub_date = models.DateTimeField(''date published'')
        tags = models.ManyToManyField(''Tag'', blank=True)
        owner = models.ForeignKey(''UserProfile'')
        content = models.ImageField(upload_to=''instaton'')

        def __unicode__(self):
                return self.name

class Comment(models.Model):
        content = models.CharField(max_length=500)
        date = models.DateTimeField(''date commented'')
        commenter = models.ForeignKey(''UserProfile'')
        pic = models.ForeignKey(''Picture'')

        def __unicode__(self):
                return self.content

Answer 1

Cuando define un administrador de usuario personalizado en admin.py su aplicación, primero debe admin.py registro del administrador de modelo de User predeterminado antes de registrar el suyo propio.

admin.site.unregister(User)
admin.site.register(User, MyUserAdmin)