unico - SQL Server 2008- Obtener restricciones de tabla

unique sql server

Question

¿Podría ayudarme a enmarcar una consulta que recupere las restricciones en todas las tablas, el recuento de restricciones en cada tabla y también mostrar NULL para las tablas que NO tienen ninguna restricción? Thx por adelantado!

Esto es lo que tengo hasta ahora:

Select SysObjects.[Name] As [Constraint Name] ,
Tab.[Name] as [Table Name],
Col.[Name] As [Column Name]
From SysObjects Inner Join
(Select [Name],[ID] From SysObjects) As Tab
On Tab.[ID] = Sysobjects.[Parent_Obj]
Inner Join sysconstraints On sysconstraints.Constid = Sysobjects.[ID]
Inner Join SysColumns Col On Col.[ColID] = sysconstraints.[ColID] And Col.[ID] = Tab.[ID]
order by [Tab].[Name]

Answer 1

Debe usar las vistas del catálogo del sistema actual (si está en SQL Server 2005 o posterior, las vistas de sysobjects están en desuso y deben evitarse), consulte la extensa documentación de Libros en pantalla de MSDN SQL Server en las vistas de catálogo aquí .

Hay bastantes puntos de vista que pueden interesarle:

• sys.default_constraints para las restricciones predeterminadas en las columnas
• sys.check_constraints para verificar las restricciones en las columnas
• sys.key_constraints para restricciones de clave (por ejemplo, claves principales)
• sys.foreign_keys para relaciones de clave foránea

y mucho más - ¡compruébalo!

Puede consultar y unirse a esas vistas para obtener la información necesaria; por ejemplo, enumerará las tablas, columnas y todas las restricciones predeterminadas definidas en ellas:

SELECT
TableName = t.Name,
ColumnName = c.Name,
dc.Name,
dc.definition
FROM sys.tables t
INNER JOIN sys.default_constraints dc ON t.object_id = dc.parent_object_id
INNER JOIN sys.columns c ON dc.parent_object_id = c.object_id AND c.column_id = dc.parent_column_id
ORDER BY t.Name

Answer 2

Puede obtener esta consulta

Restricción única,

Restricción predeterminada con valor,

Clave externa con tabla y columna referenciadas

Y Restricción de clave primaria.

Select C.*, (Select definition From sys.default_constraints Where object_id = C.object_id) As dk_definition,
(Select definition From sys.check_constraints Where object_id = C.object_id) As ck_definition,
(Select name From sys.objects Where object_id = D.referenced_object_id) As fk_table,
(Select name From sys.columns Where column_id = D.parent_column_id And object_id = D.parent_object_id) As fk_col
From sys.objects As C
Left Join (Select * From sys.foreign_key_columns) As D On D.constraint_object_id = C.object_id
Where C.parent_object_id = (Select object_id From sys.objects Where type = ''U''
And name = ''Table Name Here'');

Answer 3

Traté de editar la answer proporcionada por pero no fue aceptada por alguna razón. Formatea el sql para facilitar la lectura, incluye el esquema y también nombra el nombre predeterminado para que pueda pegarse fácilmente en otro código.

 SELECT SchemaName = s.Name,
TableName = t.Name,
ColumnName = c.Name,
DefaultName = dc.Name,
DefaultDefinition = dc.Definition
FROM sys.schemas s
JOIN sys.tables t on t.schema_id = s.schema_id
JOIN sys.default_constraints dc on dc.parent_object_id = t.object_id
JOIN sys.columns c on c.object_id = dc.parent_object_id
and c.column_id = dc.parent_column_id
ORDER BY s.Name, t.Name, c.name

Answer 4

Utilicé la siguiente consulta para recuperar la información de las restricciones en SQL Server 2012, y funciona perfectamente. Espero que te sea útil.

SELECT
tab.name AS [Table]
,tab.id AS [Table Id]
,constr.name AS [Constraint Name]
,constr.xtype AS [Constraint Type]
,CASE constr.xtype WHEN ''PK'' THEN ''Primary Key'' WHEN ''UQ'' THEN ''Unique'' ELSE '''' END AS [Constraint Name]
,i.index_id AS [Index ID]
,ic.column_id AS [Column ID]
,clmns.name AS [Column Name]
,clmns.max_length AS [Column Max Length]
,clmns.precision AS [Column Precision]
,CASE WHEN clmns.is_nullable = 0 THEN ''NO'' ELSE ''YES'' END AS [Column Nullable]
,CASE WHEN clmns.is_identity = 0 THEN ''NO'' ELSE ''YES'' END AS [Column IS IDENTITY]
FROM SysObjects AS tab
INNER JOIN SysObjects AS constr ON(constr.parent_obj = tab.id AND constr.type = ''K'')
INNER JOIN sys.indexes AS i ON( (i.index_id > 0 and i.is_hypothetical = 0) AND (i.object_id=tab.id) AND i.name = constr.name )
INNER JOIN sys.index_columns AS ic ON (ic.column_id > 0 and (ic.key_ordinal > 0 or ic.partition_ordinal = 0 or ic.is_included_column != 0))
AND (ic.index_id=CAST(i.index_id AS int)
AND ic.object_id=i.object_id)
INNER JOIN sys.columns AS clmns ON clmns.object_id = ic.object_id and clmns.column_id = ic.column_id
WHERE tab.xtype = ''U''
ORDER BY tab.name

Answer 5

SELECT
[oj].[name] [TableName],
[ac].[name] [ColumnName],
[dc].[name] [DefaultConstraintName],
[dc].[definition]
FROM
sys.default_constraints [dc],
sys.all_objects [oj],
sys.all_columns [ac]
WHERE
(
([oj].[type] IN (''u'')) AND
([oj].[object_id] = [dc].[parent_object_id]) AND
([oj].[object_id] = [ac].[object_id]) AND
([dc].[parent_column_id] = [ac].[column_id])
)