mostrar - Cómo publicar datos JSON con PHP cURL?

receive json php post

Question

Aquí está mi código,

 $url = ''url_to_post'';
$data = array("first_name" => "First name","last_name" => "last name","email"=>"[email protected]","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" => "Mother","last_name" => "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) );
$data_string = json_encode($data);
$ch=curl_init($url);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, array("customer"=>$data_string));
curl_setopt($ch, CURLOPT_HEADER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER,
array(''Content-Type:application/json'',
''Content-Length: '' . strlen($data_string))
);
$result = curl_exec($ch);
curl_close($ch);

Y en otra página, estoy recuperando datos de la publicación.

 print_r ($_POST);

La salida es

HTTP/1.1 200 OK
Date: Mon, 18 Jun 2012 07:58:11 GMT
Server: Apache
X-Powered-By: PHP/5.3.6
Vary: Accept-Encoding
Connection: close
Content-Type: text/html
Array ( )

Por lo tanto, no obtengo los datos adecuados incluso en mi propio servidor, es una matriz vacía. Quiero implementar REST usando json como en http://docs.shopify.com/api/customer#create

Answer 1

Estás PUBLICANDO el json incorrectamente, pero incluso si fuera correcto, no podrías probar usando print_r($_POST) ( lee por qué aquí ). En cambio, en su segunda página, puede capturar la solicitud entrante utilizando file_get_contents("php://input") , que contendrá el jSON POST . Para ver los datos recibidos en un formato más legible, intente esto:

echo ''<pre>''.print_r(json_decode(file_get_contents("php://input")),1).''</pre>'';

En su código, está indicando Content-Type:application/json , pero no está codificando json todos los datos POST, solo el valor del campo POST "cliente". En cambio, haz algo como esto:

$ch = curl_init( $url );
# Setup request to send json via POST.
$payload = json_encode( array( "customer"=> $data ) );
curl_setopt( $ch, CURLOPT_POSTFIELDS, $payload );
curl_setopt( $ch, CURLOPT_HTTPHEADER, array(''Content-Type:application/json''));
# Return response instead of printing.
curl_setopt( $ch, CURLOPT_RETURNTRANSFER, true );
# Send request.
$result = curl_exec($ch);
curl_close($ch);
# Print response.
echo "<pre>$result</pre>";

Nota: Puede beneficiarse del uso de una biblioteca de terceros en lugar de interactuar directamente con la API de Shopify.

Answer 2

Por favor prueba este código: -

$url = ''url_to_post'';
$data = array("first_name" => "First name","last_name" => "last name","email"=>"[email protected]","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" => "Mother","last_name" => "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) );
$data_string = json_encode(array("customer" =>$data));
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(''Content-Type:application/json''));
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$result = curl_exec($ch);
curl_close($ch);
echo "$result";

Answer 3

Prueba este ejemplo.

<?php
$url = ''http://localhost/test/page2.php'';
$data = array("first_name" => "First name","last_name" => "last name","email"=>"[email protected]","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" => "Mother","last_name" => "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) );
$ch=curl_init($url);
$data_string = urlencode(json_encode($data));
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, array("customer"=>$data_string));
$result = curl_exec($ch);
curl_close($ch);
echo $result;
?>

Su código page2.php

<?php
$datastring = $_POST[''customer''];
$data = json_decode( urldecode( $datastring));
?>

Answer 4

Pruebe de esta manera:

$url = ''url_to_post'';
// this is only part of the data you need to sen
$customer_data = array("first_name" => "First name","last_name" => "last name","email"=>"[email protected]","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" => "Mother","last_name" => "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) );
// As per your API, the customer data should be structured this way
$data = array("customer" => $customer_data);
// And then encoded as a json string
$data_string = json_encode($data);
$ch=curl_init($url);
curl_setopt_array($ch, array(
CURLOPT_POST => true,
CURLOPT_POSTFIELDS => $data_string,
CURLOPT_HEADER => true,
CURLOPT_HTTPHEADER => array(''Content-Type:application/json'', ''Content-Length: '' . strlen($data_string)))
));
$result = curl_exec($ch);
curl_close($ch);

La clave que has olvidado es json_encode tus datos. Pero también puede resultarle conveniente usar curl_setopt_array para configurar todas las opciones de curl a la vez pasando una matriz.

Answer 5

Reemplazar

curl_setopt($ch, CURLOPT_POSTFIELDS, array("customer"=>$data_string));

con:

$data_string = json_encode(array("customer"=>$data));
//Send blindly the json-encoded string.
//The server, IMO, expects the body of the HTTP request to be in JSON
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);

No entiendo lo que querías decir con "otra página", espero que sea la página en: ''url_to_post''. Si esa página está escrita en PHP, el JSON que acaba de publicar se leerá de la siguiente manera:

$jsonStr = file_get_contents("php://input"); //read the HTTP body.
$json = json_decode($jsonStr);