javascript - desc - lodash remove from array

Filtrar una matriz de objetos con lodash basado en el valor de la propiedad

Question

Tenemos una variedad de objetos como tales

var myArr = [ {name: "john", age:23}
{name: "john", age:43}
{name: "jim", age:101}
{name: "bob", age:67} ];

¿cómo obtengo la lista de objetos de myArr donde el nombre es john con lodash?

Answer 1

Con lodash :

const myArr = [ {name: "john", age:23},
{name: "john", age:43},
{name: "jim", age:101},
{name: "bob", age:67} ];
const johnArr = _.filter(myArr, person => person.name === ''john'');
console.log(johnArr)

JavaScript Vanilla:

const myArr = [ {name: "john", age:23},
{name: "john", age:43},
{name: "jim", age:101},
{name: "bob", age:67} ];
const johnArr = myArr.filter(person => person.name === ''john'');
console.log(johnArr);

Answer 2

Lodash tiene una función de "mapa" que funciona como jQuerys:

var myArr = [{ name: "john", age:23 },
{ name: "john", age:43 },
{ name: "jimi", age:10 },
{ name: "bobi", age:67 }];
var johns = _.map(myArr, function(o) {
if (o.name == "john") return o;
});
// Remove undefines from the array
johns = _.without(johns, undefined)

Answer 3

Use el método lodash _.filter :

_.filter(collection, [predicate=_.identity])

Itera sobre los elementos de la colección, devolviendo una matriz de todos los elementos por los que predicate devuelve truthy. El predicado se invoca con tres argumentos: (valor, índice | clave, colección).

con predicado como función personalizada

 _.filter(myArr, function(o) {
return o.name == ''john'';
});

con predicado como parte del objeto filtrado (la taquigrafía _.matches _.matches)

_.filter(myArr, {name: ''john''});

con predicado como matriz [clave, valor] (la taquigrafía _.matchesProperty _.matchesProperty).

_.filter(myArr, [''name'', ''John'']);

Answer 4

lodash también tiene un método de eliminación

 var myArr = [ {name: "john", age:23}
{name: "john", age:43}
{name: "jim", age:101}
{name: "bob", age:67} ];
var onlyJohn = myArr.remove( person => { return person.name == "john" })

Answer 5

let myArr = [
{name: "john", age:23},
{name: "john", age:43},
{name: "jim", age:101},
{name: "bob", age:67},
];
// this will return old object (myArr) with items named ''john''
let list = _.filter(myArr, item => item.name === ''jhon'');
// this will return new object referenc (new Object) with items named ''john''
let list = _.map(myArr, item => item.name === ''jhon'').filter(item => item.name);

Answer 6

let myArr = [
{name: "john", age:23},
{name: "john", age:43},
{name: "jim", age:101},
{name: "bob", age:67},
];
let list = _.filter(myArr, item => item.name === "john");