javascript - desc - lodash remove from array

Filtrar una matriz de objetos con lodash basado en el valor de la propiedad

Question

Tenemos una variedad de objetos como tales

var myArr = [ {name: "john", age:23}
              {name: "john", age:43}
              {name: "jim", age:101}
              {name: "bob", age:67} ];

¿cómo obtengo la lista de objetos de myArr donde el nombre es john con lodash?

Answer 1

Con lodash :

const myArr = [ {name: "john", age:23},
                {name: "john", age:43},
                {name: "jim", age:101},
                {name: "bob", age:67} ];

const johnArr = _.filter(myArr, person => person.name === ''john'');
console.log(johnArr)

JavaScript Vanilla:

const myArr = [ {name: "john", age:23},
                {name: "john", age:43},
                {name: "jim", age:101},
                {name: "bob", age:67} ];

const johnArr = myArr.filter(person => person.name === ''john'');
console.log(johnArr);

Answer 2

Lodash tiene una función de "mapa" que funciona como jQuerys:

var myArr =  [{ name: "john", age:23 },
              { name: "john", age:43 },
              { name: "jimi", age:10 },
              { name: "bobi", age:67 }];

var johns = _.map(myArr, function(o) {
    if (o.name == "john") return o;
});

// Remove undefines from the array
johns = _.without(johns, undefined)

Answer 3

Use el método lodash _.filter :

_.filter(collection, [predicate=_.identity])

Itera sobre los elementos de la colección, devolviendo una matriz de todos los elementos por los que predicate devuelve truthy. El predicado se invoca con tres argumentos: (valor, índice | clave, colección).

con predicado como función personalizada

 _.filter(myArr, function(o) { 
    return o.name == ''john''; 
 });

con predicado como parte del objeto filtrado (la taquigrafía _.matches _.matches)

_.filter(myArr, {name: ''john''});

con predicado como matriz [clave, valor] (la taquigrafía _.matchesProperty _.matchesProperty).

_.filter(myArr, [''name'', ''John'']);

Answer 4

lodash también tiene un método de eliminación

 var myArr = [ {name: "john", age:23}
          {name: "john", age:43}
          {name: "jim", age:101}
          {name: "bob", age:67} ];

 var onlyJohn = myArr.remove( person => { return person.name == "john" })

Answer 5

let myArr = [
    {name: "john", age:23},
    {name: "john", age:43},
    {name: "jim", age:101},
    {name: "bob", age:67},
];

// this will return old object (myArr) with items named ''john''
let list = _.filter(myArr, item => item.name === ''jhon'');

//  this will return new object referenc (new Object) with items named ''john'' 
let list = _.map(myArr, item => item.name === ''jhon'').filter(item => item.name);

Answer 6

let myArr = [
    {name: "john", age:23},
    {name: "john", age:43},
    {name: "jim", age:101},
    {name: "bob", age:67},
];

let list = _.filter(myArr, item => item.name === "john");