vb.net - example - vb net post request

HTTP GET en VB.NET

Question

¿Cuál es la mejor forma de emitir un http get en VB.net? Quiero obtener el resultado de una solicitud como http://api.hostip.info/?ip=68.180.206.184

Answer 1

Deberías probar la clase http://msdn.microsoft.com/en-us/library/system.net.httpwebrequest.aspx .

Answer 2

En VB.NET:

Dim webClient As New System.Net.WebClient
Dim result As String = webClient.DownloadString("http://api.hostip.info/?ip=68.180.206.184")

Cª#:

System.Net.WebClient webClient = new System.Net.WebClient();
string result = webClient.DownloadString("http://api.hostip.info/?ip=68.180.206.184");

Answer 3

La forma más fácil es System.Net.WebClient.DownloadFile o DownloadString .

Answer 4

Prueba esto:

WebRequest request = WebRequest.CreateDefault(RequestUrl);
request.Method = "GET";
WebResponse response;
try { response = request.GetResponse(); }
catch (WebException exc) { response = exc.Response; }
if (response == null)
throw new HttpException((int)HttpStatusCode.NotFound, "The requested url could not be found.");
using(StreamReader reader = new StreamReader(response.GetResponseStream())) {
string requestedText = reader.ReadToEnd();
// do what you want with requestedText
}

Perdón por la C #, sé que solicitaste VB, pero no tuve tiempo de convertir.

Answer 5

Puede usar la clase HttpWebRequest para realizar una solicitud y recuperar una respuesta de una URL determinada. Lo usarás como:

Try
Dim fr As System.Net.HttpWebRequest
Dim targetURI As New Uri("http://whatever.you.want.to.get/file.html")
fr = DirectCast(HttpWebRequest.Create(targetURI), System.Net.HttpWebRequest)
If (fr.GetResponse().ContentLength > 0) Then
Dim str As New System.IO.StreamReader(fr.GetResponse().GetResponseStream())
Response.Write(str.ReadToEnd())
str.Close();
End If
Catch ex As System.Net.WebException
''Error in accessing the resource, handle it
End Try

HttpWebRequest se detalla en: http://msdn.microsoft.com/en-us/library/system.net.httpwebrequest.aspx

Una segunda opción es usar la clase WebClient, esto proporciona una interfaz más fácil de usar para descargar recursos web pero no es tan flexible como HttpWebRequest:

Sub Main()
''Address of URL
Dim URL As String = http://whatever.com
'' Get HTML data
Dim client As WebClient = New WebClient()
Dim data As Stream = client.OpenRead(URL)
Dim reader As StreamReader = New StreamReader(data)
Dim str As String = ""
str = reader.ReadLine()
Do While str.Length > 0
Console.WriteLine(str)
str = reader.ReadLine()
Loop
End Sub

Se puede encontrar más información sobre el cliente web en: http://msdn.microsoft.com/en-us/library/system.net.webclient.aspx

Answer 6

usa la clase webrequest

esto es para obtener una imagen

 Try
Dim _WebRequest As System.Net.WebRequest = Nothing
_WebRequest = System.Net.WebRequest.Create(http://api.hostip.info/?ip=68.180.206.184)
Catch ex As Exception
Windows.Forms.MessageBox.Show(ex.Message)
Exit Sub
End Try
Try
_NormalImage = Image.FromStream(_WebRequest.GetResponse().GetResponseStream())
Catch ex As Exception
Windows.Forms.MessageBox.Show(ex.Message)
Exit Sub
End Try

Answer 7

Public Function getLoginresponce(ByVal email As String, ByVal password As String) As String
Dim requestUrl As String = "your api"
Dim request As HttpWebRequest = TryCast(WebRequest.Create(requestUrl), HttpWebRequest)
Dim response As HttpWebResponse = TryCast(request.GetResponse(), HttpWebResponse)
Dim dataStream As Stream = response.GetResponseStream()
Dim reader As New StreamReader(dataStream)
Dim responseFromServer As String = reader.ReadToEnd()
Dim result = responseFromServer
reader.Close()
response.Close()
Return result
End Function