objective-c - how to exit vim

¿Un simple post de http en Objective-C?

Question

Tengo una página web php que requiere un inicio de sesión (ID de usuario y contraseña). El usuario ingresó la información en la aplicación, muy bien ... pero necesito un ejemplo sobre cómo hacer una solicitud POST a un sitio web. El ejemplo de Apple en el sitio de soporte es bastante complicado y muestra una carga de imágenes ... el mío debería ser más simple. Solo quiero publicar 2 líneas de texto. ¿Alguien tiene algún buen ejemplo?

Alex

Answer 1

Aquí estoy agregando un código de muestra para la respuesta http post print y analizando como JSON, si es posible, manejará todo de manera asíncrona, por lo que su GUI se actualizará perfectamente y no se paralizará en absoluto, lo cual es importante notar.

//POST DATA
NSString *theBody = [NSString stringWithFormat:@"parameter=%@",YOUR_VAR_HERE];
NSData *bodyData = [theBody dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
//URL CONFIG
NSString *serverURL = @"https://your-website-here.com";
NSString *downloadUrl = [NSString stringWithFormat:@"%@/your-friendly-url-here/json",serverURL];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString: downloadUrl]];
//POST DATA SETUP
[request setHTTPMethod:@"POST"];
[request setHTTPBody:bodyData];
//DEBUG MESSAGE
NSLog(@"Trying to call ws %@",downloadUrl);
//EXEC CALL
[NSURLConnection sendAsynchronousRequest:request queue:[NSOperationQueue currentQueue] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {
if (error) {
NSLog(@"Download Error:%@",error.description);
}
if (data) {
//
// THIS CODE IS FOR PRINTING THE RESPONSE
//
NSString *returnString = [[NSString alloc] initWithData:data encoding: NSUTF8StringEncoding];
NSLog(@"Response:%@",returnString);
//PARSE JSON RESPONSE
NSDictionary *json_response = [NSJSONSerialization JSONObjectWithData:data
options:0
error:NULL];
if ( json_response ) {
if ( [json_response isKindOfClass:[NSDictionary class]] ) {
// do dictionary things
for ( NSString *key in [json_response allKeys] ) {
NSLog(@"%@: %@", key, json_response[key]);
}
}
else if ( [json_response isKindOfClass:[NSArray class]] ) {
NSLog(@"%@",json_response);
}
}
else {
NSLog(@"Error serializing JSON: %@", error);
NSLog(@"RAW RESPONSE: %@",data);
NSString *returnString2 = [[NSString alloc] initWithData:data encoding: NSUTF8StringEncoding];
NSLog(@"Response:%@",returnString2);
}
}
}];

¡Espero que esto ayude!

Answer 2

Muchas gracias funcionó, ten en cuenta que hice un error tipográfico en PHP ya que debería ser mysqli_query ($ con2, $ sql)

Answer 3

Puedes hacerlo usando dos opciones:

Usando NSURLConnection:

NSURL* URL = [NSURL URLWithString:@"http://www.example.com/path"];
NSMutableURLRequest* request = [NSMutableURLRequest requestWithURL:URL];
request.HTTPMethod = @"POST";
// Form URL-Encoded Body
NSDictionary* bodyParameters = @{
@"username": @"reallyrambody",
@"password": @"123456"
};
request.HTTPBody = [NSStringFromQueryParameters(bodyParameters) dataUsingEncoding:NSUTF8StringEncoding];
// Connection
NSURLConnection* connection = [NSURLConnection connectionWithRequest:request delegate:nil];
[connection start];
/*
* Utils: Add this section before your class implementation
*/
/**
This creates a new query parameters string from the given NSDictionary. For
example, if the input is @{@"day":@"Tuesday", @"month":@"January"}, the output
string will be @"day=Tuesday&month=January".
@param queryParameters The input dictionary.
@return The created parameters string.
*/
static NSString* NSStringFromQueryParameters(NSDictionary* queryParameters)
{
NSMutableArray* parts = [NSMutableArray array];
[queryParameters enumerateKeysAndObjectsUsingBlock:^(id key, id value, BOOL *stop) {
NSString *part = [NSString stringWithFormat: @"%@=%@",
[key stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding],
[value stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding]
];
[parts addObject:part];
}];
return [parts componentsJoinedByString: @"&"];
}
/**
Creates a new URL by adding the given query parameters.
@param URL The input URL.
@param queryParameters The query parameter dictionary to add.
@return A new NSURL.
*/
static NSURL* NSURLByAppendingQueryParameters(NSURL* URL, NSDictionary* queryParameters)
{
NSString* URLString = [NSString stringWithFormat:@"%@?%@",
[URL absoluteString],
NSStringFromQueryParameters(queryParameters)
];
return [NSURL URLWithString:URLString];
}

Usando NSURLSession

- (void)sendRequest:(id)sender
{
/* Configure session, choose between:
* defaultSessionConfiguration
* ephemeralSessionConfiguration
* backgroundSessionConfigurationWithIdentifier:
And set session-wide properties, such as: HTTPAdditionalHeaders,
HTTPCookieAcceptPolicy, requestCachePolicy or timeoutIntervalForRequest.
*/
NSURLSessionConfiguration* sessionConfig = [NSURLSessionConfiguration defaultSessionConfiguration];
/* Create session, and optionally set a NSURLSessionDelegate. */
NSURLSession* session = [NSURLSession sessionWithConfiguration:sessionConfig delegate:nil delegateQueue:nil];
/* Create the Request:
Token Duplicate (POST http://www.example.com/path)
*/
NSURL* URL = [NSURL URLWithString:@"http://www.example.com/path"];
NSMutableURLRequest* request = [NSMutableURLRequest requestWithURL:URL];
request.HTTPMethod = @"POST";
// Form URL-Encoded Body
NSDictionary* bodyParameters = @{
@"username": @"reallyram",
@"password": @"123456"
};
request.HTTPBody = [NSStringFromQueryParameters(bodyParameters) dataUsingEncoding:NSUTF8StringEncoding];
/* Start a new Task */
NSURLSessionDataTask* task = [session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
if (error == nil) {
// Success
NSLog(@"URL Session Task Succeeded: HTTP %ld", ((NSHTTPURLResponse*)response).statusCode);
}
else {
// Failure
NSLog(@"URL Session Task Failed: %@", [error localizedDescription]);
}
}];
[task resume];
}
/*
* Utils: Add this section before your class implementation
*/
/**
This creates a new query parameters string from the given NSDictionary. For
example, if the input is @{@"day":@"Tuesday", @"month":@"January"}, the output
string will be @"day=Tuesday&month=January".
@param queryParameters The input dictionary.
@return The created parameters string.
*/
static NSString* NSStringFromQueryParameters(NSDictionary* queryParameters)
{
NSMutableArray* parts = [NSMutableArray array];
[queryParameters enumerateKeysAndObjectsUsingBlock:^(id key, id value, BOOL *stop) {
NSString *part = [NSString stringWithFormat: @"%@=%@",
[key stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding],
[value stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding]
];
[parts addObject:part];
}];
return [parts componentsJoinedByString: @"&"];
}
/**
Creates a new URL by adding the given query parameters.
@param URL The input URL.
@param queryParameters The query parameter dictionary to add.
@return A new NSURL.
*/
static NSURL* NSURLByAppendingQueryParameters(NSURL* URL, NSDictionary* queryParameters)
{
NSString* URLString = [NSString stringWithFormat:@"%@?%@",
[URL absoluteString],
NSStringFromQueryParameters(queryParameters)
];
return [NSURL URLWithString:URLString];
}

Answer 4

Qué tal si

NSString *post = @"key1=val1&key2=val2";
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];
NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease];
[request setURL:[NSURL URLWithString:@"http://www.nowhere.com/sendFormHere.php"]];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:postData];

Tomado de http://deusty.blogspot.com/2006/11/sending-http-get-and-post-from-cocoa.html . Eso es lo que utilicé recientemente, y funcionó bien para mí.

Por cierto, 5 segundos de búsqueda de Google habrían permitido el mismo resultado, usando los términos "post request cocoa";)

Answer 5

Soy un principiante en las aplicaciones de iPhone y todavía tengo un problema, aunque seguí los consejos anteriores. Parece que las variables POST no son recibidas por mi servidor, no estoy seguro si provienen del código php o object-c ...

la parte objetivo-c (codificada siguiendo el protocolo de Chris metodo)

// Create the request.
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://example.php"]];
// Specify that it will be a POST request
request.HTTPMethod = @"POST";
// This is how we set header fields
[request setValue:@"application/xml; charset=utf-8" forHTTPHeaderField:@"Content-Type"];
// Convert your data and set your request''s HTTPBody property
NSString *stringData = [NSString stringWithFormat:@"user_name=%@&password=%@", self.userNameField.text , self.passwordTextField.text];
NSData *requestBodyData = [stringData dataUsingEncoding:NSUTF8StringEncoding];
request.HTTPBody = requestBodyData;
// Create url connection and fire request
//NSURLConnection *conn = [[NSURLConnection alloc] initWithRequest:request delegate:self];
NSData *response = [NSURLConnection sendSynchronousRequest:request
returningResponse:nil error:nil];
NSLog(@"Response: %@",[[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding]);

Debajo de la parte php:

if (isset($_POST[''user_name''],$_POST[''password'']))
{
// Create connection
$con2=mysqli_connect($servername, $username, $password, $dbname);
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
else
{
// retrieve POST vars
$username = $_POST[''user_name''];
$password = $_POST[''password''];
$sql = "INSERT INTO myTable (user_name, password) VALUES (''$username'', ''$password'')";
$retval = mysqli_query( $sql, $con2 );
if(! $retval )
{
die(''Could not enter data: '' . mysql_error());
}
echo "Entered data successfully/n";
mysqli_close($con2);
}
}
else
{
echo "No data input in php";
}

He estado estancado los últimos días en este.

Answer 6

ASIHTTPRequest hace la comunicación en red realmente fácil

ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:url];
[request addPostValue:@"Ben" forKey:@"names"];
[request addPostValue:@"George" forKey:@"names"];
[request addFile:@"/Users/ben/Desktop/ben.jpg" forKey:@"photos"];
[request addData:imageData withFileName:@"george.jpg" andContentType:@"image/jpeg" forKey:@"photos"];

Answer 7

Desde el sitio web oficial de Apple :

// In body data for the ''application/x-www-form-urlencoded'' content type,
// form fields are separated by an ampersand. Note the absence of a
// leading ampersand.
NSString *bodyData = @"name=Jane+Doe&address=123+Main+St";
NSMutableURLRequest *postRequest = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"https://www.apple.com"]];
// Set the request''s content type to application/x-www-form-urlencoded
[postRequest setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
// Designate the request a POST request and specify its body data
[postRequest setHTTPMethod:@"POST"];
[postRequest setHTTPBody:[NSData dataWithBytes:[bodyData UTF8String] length:strlen([bodyData UTF8String])]];
// Initialize the NSURLConnection and proceed as described in
// Retrieving the Contents of a URL

De: código con chris

 // Create the request.
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://google.com"]];
// Specify that it will be a POST request
request.HTTPMethod = @"POST";
// This is how we set header fields
[request setValue:@"application/xml; charset=utf-8" forHTTPHeaderField:@"Content-Type"];
// Convert your data and set your request''s HTTPBody property
NSString *stringData = @"some data";
NSData *requestBodyData = [stringData dataUsingEncoding:NSUTF8StringEncoding];
request.HTTPBody = requestBodyData;
// Create url connection and fire request
NSURLConnection *conn = [[NSURLConnection alloc] initWithRequest:request delegate:self];

Answer 8

 NSMutableDictionary *contentDictionary = [[NSMutableDictionary alloc]init];
[contentDictionary setValue:@"name" forKey:@"email"];
[contentDictionary setValue:@"name" forKey:@"username"];
[contentDictionary setValue:@"name" forKey:@"password"];
[contentDictionary setValue:@"name" forKey:@"firstName"];
[contentDictionary setValue:@"name" forKey:@"lastName"];
NSData *data = [NSJSONSerialization dataWithJSONObject:contentDictionary options:NSJSONWritingPrettyPrinted error:nil];
NSString *jsonStr = [[NSString alloc] initWithData:data
encoding:NSUTF8StringEncoding];
NSLog(@"%@",jsonStr);
NSString *urlString = [NSString stringWithFormat:@"http://testgcride.com:8081/v1/users"];
NSURL *url = [NSURL URLWithString:urlString];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request setHTTPMethod:@"POST"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:[jsonStr dataUsingEncoding:NSUTF8StringEncoding]];
AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
[manager.requestSerializer setAuthorizationHeaderFieldWithUsername:@"moinsam" password:@"cheese"];
manager.requestSerializer = [AFJSONRequestSerializer serializer];
AFHTTPRequestOperation *operation = [manager HTTPRequestOperationWithRequest:request success:<block> failure:<block>];